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Georgia [21]
3 years ago
8

How can people reduce respiratory Diseases & Accidents?

Chemistry
1 answer:
kirill [66]3 years ago
6 0

Respiratory diseases can be prevented. Avoiding exposure to tobacco smoke, home and workplace air pollutants, and respiratory infections can prevent the development of COPD. Smoking is the most common cause of chronic respiratory diseases like COPD. Smoking cessation is the most important part of treatment for smokers diagnosed with chronic respiratory disease. Indoor and outdoor air pollutants cam also cause respiratory problems. Air pollution can irritate, inflame, or destroy lung tissue. Washing hands regularly with soap and water can prevent respiratory infections. It is estimated that hands spread 80 percent of common infectious respiratory diseases like colds and flu. Early detection of respiratory diseases might change disease course and progress. A simple test, called spirometry can be used to measure pulmonary—or lung—function and detect COPD in anyone with breathing problems.

Hope this helps!


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A compound with the molecular formula C10H10O4 produces a 1H NMR spectrum that exhibits only two signals, both singlets. One sig
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Answer:

The attached figure shows the structure of dimethyl terephthalate.

Explanation:

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How would I find the number of protons, neutrons and electrons when I only have the atomic number and atom (assignment says assu
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But for the neutron there is no specific technique. You have to remember the neutrons of every element

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Attached is the answer

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3 years ago
The activation energy of an uncatalyzed reaction is 70 kJ/mol. When a catalyst is added, the activation energy (at 20 °C) is 42
denis23 [38]

Answer:

T = 215.33 °C

Explanation:

The activation energy is given by the Arrhenius equation:

k = Ae^{\frac{-Ea}{RT}}

<u>Where:</u>

k: is the rate constant

A: is the frequency factor    

Ea: is the activation energy

R: is the gas constant = 8.314 J/(K*mol)

T: is the temperature

We have for the uncatalyzed reaction:

Ea₁ = 70 kJ/mol

And for the catalyzed reaction:

Ea₂ = 42 kJ/mol

T₂ = 20 °C = 293 K

The frequency factor A is constant and the initial concentrations are the same.

Since the rate of the uncatalyzed reaction (k₁) is equal to the rate of the catalyzed reaction (k₂), we have:

k_{1} = k_{2}

Ae^{\frac{-Ea_{1}}{RT_{1}}} = Ae^{\frac{-Ea_{2}}{RT_{2}}}   (1)

By solving equation (1) for T₁ we have:

T_{1} = \frac{T_{2}*Ea_{1}}{Ea_{2}} = \frac{293 K*70 kJ/mol}{42 kJ/mol} = 488. 33 K = 215.33 ^\circ C  

Therefore, we need to heat the solution at 215.33 °C so that the rate of the uncatalyzed reaction is equal to the rate of the catalyzed reaction.

I hope it helps you!      

4 0
3 years ago
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