Question

Consider two objects (Object 1 and Object 2) moving in the same direction on a frictionless surface. Object 1 moves with speed v1=v and has mass m1=2m. Object 2 moves with speed v2=2–√v and has mass m2=m.

Answer 1

Answer:

First object has greater magnitude of momentum.

Explanation:

Given that,

Speed of first object = v

Mass of first object = 2m

Speed of second object = 2√v

Mass of second object = m

Suppose we find which object has the larger magnitude of its momentum

We need to calculate the momentum of first object

Using formula of momentum

$P=mv$

Where, m = mass of first object

v = speed of first object

Put the value into the formula

$P_{1}=2m\times v$

$P_{1}=2mv$...(I)

We need to calculate the momentum of second object

Using formula of momentum

$P=mv$

Where, m = mass of second object

v = speed of second object

Put the value into the formula

$P_{2}=m\times 2\sqrt{v}$

$P_{2}=m2\sqrt{v}$....(II)

On comparing equation (I) and (II)

Hence, First object has greater magnitude of momentum.