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Oxana [17]
4 years ago
6

The springs of a 1800 kg car compress 5.4 mm when its 66 kg driver gets into the driver's seat. If the car goes over a bump, wha

t will be the frequency of oscillations

Physics
1 answer:
almond37 [142]4 years ago
8 0

Explanation:

Below is an attachment containing the solution.

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The pulley is a uniform disk with a mass of 0.75 kg and a radius of 6.5
larisa [96]

Answer:

please find the answer in the attached images , in 2 parts, btw thanks for so many points. i hope my answers are correct.

5 0
3 years ago
Read 2 more answers
Which statements describe elements? Check all that apply.
solmaris [256]
The answers are B, C, E and F.

Atoms from an element is mostly made of protons, neutrons, and electrons. Proton numbers are like a class number for each element. Each element has their own and they're all different. And the number of protons are equal to the number of electrons. Therefore, B is correct.

Isotopes. It's different atoms from a same element that has the same number of protons but different number of neutrons. For example in hydrogen, there's 3 Isotopes for hydrogen. Therefore, C is correct.

Again, proton for the same element is never changed, even if they're different Isotopes. So, E is correct.

Isotopes, again, different elements may have different Isotopes. Some has only 1, others may have a few or more. So, F is correct too.
8 0
4 years ago
Read 2 more answers
Jim strikes a 0.058 kg golf ball with a force of 272 N, giving it a velocity of 62.0 m/s. How long was the ball in contact with
Mekhanik [1.2K]

Answer: 0.013 seconds

Explanation:

Given that

Mass of golf ball = 0.058 kg

Force = 272 N

Velocity = 62.0 m/s

Time taken = ?

Recall that force is the rate of change of momentum per unit time

i.e Force = Change in momentum / Time

i.e Force = (Mass x velocity) / Time

272N = (0.058 kg x 62.0 m/s) / Time

272N = 3.6kgm/s / Time

Time = (3.6kgm/s / 272N)

Time = 0.013 seconds

Thus, the ball was in contact with the club for 0.013 seconds

8 0
4 years ago
A wire with a resistance of 10 ohm is stretched so that its new length is four times its original length. find the resistance of
amm1812
Let original length be L. The new length is therefore 4L.

Let original cross sectional surface area of the wire be equal to πr^2.

This means original volume was L x πr^2 = Lπr^2

The volume is the same but the length is different so 4L x new surface area must be equal to Lπr^2. Let new surface area be equal to Y.

4L x Y = Lπr^2
=> Y = (πr^2 )/ 4


Using the resistivity formula,
R = pL/A. p which is resistivity is a constant so it stays the same

But this time, instead of L we have 4L and instead of πr^2 we have (πr^2)/4.

so the new resistance
= (4Lp)/ {(πr^2)/4}
= 16 (pL)/(πr^2)
= 16 (pL)/A. because πr^2 is A
since pL/A is equal to R from the formula, this is equal to
16 R.

R was 10 ohms
therefore new resistance is 16 x 10 = 160 ohms




6 0
4 years ago
Pls help i’ll give brainliest if you give a correct answer!!
Anit [1.1K]

Answer:

south

im not sure with this answer

3 0
3 years ago
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