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3 years ago

8

If two metal balls each have a charge of -10^-6 C and the repulsive force between them is 1 N, how far apart are they? (Coulomb'

s constant is k = 9.0x 10^9 N-m^2/C^2? 9.5 m 9.0 mm 9.5 cm 0.9 m .

1 answer:

Vitek1552 [10]3 years ago

4 0

Answer:

The distance between the charges is 9.5 cm

(c) is correct option

Explanation:

Given that,

Charge $q= 10^{-6}\ C$

Force F = 1 N

We need to calculate the distance between the charges

Using Coulomb's formula

$F = \dfrac{kq_{1}q_{2}}{r^2}$

Where, q = charge

r = distance

F = force

Put the value into the formula

$1=\dfrac{9.0\times10^{9}\times(-10^{-6})^2}{r^2}$

$r=\sqrt{9\times10^{9}\times(-10^{-6})^2}$

$r=0.095\ m$

$r= 9.5\ cm$

Hence, The distance between the charges is 9.5 cm

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