Answer:
a = 603.59 m/s^2
Explanation:
from the data given . the rate of change in magnetic field is as follow

from the faraday's law of induction , the expression for the induced emf in region of radius r as follow




electric field at point P_1 as follow



from newton 2nd law of motion, the acceleration of proton is
F = ma
qE = ma


a = 603.59 m/s^2
Answer:
The energy released during nucleur fissionor fusion , espicially when used to generate
Explanation:
Distionary.
This question needs research to be answered. From the given information alone it can't be answered without making wild assumptions.
Ideally, you need to take a look at a distribution (or a histogram) of asteroid diameters, identify the "mode" of such a distribution, and find the corresponding diameter. That value will be the answer.
I am attaching one such histogram on asteroid diameters from the IRAS asteroid catalog I could find online. (In order to get a single histogram, you need to add the individual curves in the figure first). Eyeballing this sample, I'd say the mode is somewhere around 10km, so the answer would be: the diameter of most asteroid from the IRAS asteroid catalog is about 10km.
1.47x10^5 Joules
The gravitational potential energy will be the mass of the object, multiplied by the height upon which it can drop, multiplied by the local gravitational acceleration. And since it started at the top of a 60.0 meter hill, halfway will be at 30.0 meters. So
500 kg * 30.0 m * 9.8 m/s^2 = 147000 kg*m^2/s^ = 147000 Joules.
Using scientific notation and 3 significant figures gives 1.47x10^5 Joules.