Answer:
The velocity when the ball hits the ground is obtained using v2. 2 = v1. 2 + 2 g Dy with v1=0 and Dy=h. Thus solving for v2 yields 17.1 m/s v2 = 2 g h =.
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Assuming no other forces are acting on the wheelbarrow, it must be stationary.
Answer:
The height of the water slide is 0.878 m
Explanation:
Given that,
Distance = 2.52 m
Suppose Children slide down a friction less water slide that ends at a height of 1.80 m above the pool.
We need to calculate the time
Using equation of motion
Put the value in the equation
We need to calculate the velocity
Using formula of velocity
Put the value into the formula
We need to calculate height
Using conservation of energy
Put the value into the formula
Hence, The height of the water slide is 0.878 m.
This is hard sorry but I need to anwser
The cat has two directions of motions:
The horizontal motion = Dx = 2.2 m
The vertical motion = Dy = -1.3 m (negative sign indicates that the cat is falling)
a = 9.8 m/sec^2
Vy = zero (since you are not moving up)
From the laws of motion:
<span>Dy = Vyt + 0.5ayt^2
</span>-1.3 = 0(t) + 0.5(-9.8)t^2
<span>t = 0.52s
</span>
Then, again using the laws of motion (but for the horizontal direction this time)
Dx = Vxt
<span>2.2 = Vx0.52 </span>
<span>Vx = 2.2/0.52 </span>
<span>= 4.23 m/s
</span>
<span>Therefore the cat's speed when it slid off the table is 4.23 m/s horizontally.</span>
