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bagirrra123 [75]
2 years ago
15

If a heat engine takes in 4565 kJ and gives up 2955 kJ during one cycle, what is the engine’s efficiency?

Physics
1 answer:
vodomira [7]2 years ago
5 0

The engine efficiency is 64.73 %

<u>Explanation:</u>

Given data

To find the engine’s efficiency we have the formula,

Energy input- 4565 KJ

Energy output - 2955KJ

Efficiency= energy output/ energy input ×100%

 =2955/4565

  =0.6473 ×100

η               =64.73 %

The engine efficiency is 64.73 %

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A ball rolls off a table and it traveling with a horizontal velocity of 2 m/s and 1 point
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Answer:

The velocity when the ball hits the ground is obtained using v2. 2 = v1. 2 + 2 g Dy with v1=0 and Dy=h. Thus solving for v2 yields 17.1 m/s v2 = 2 g h =.

21 pages·330 KB

4 0
2 years ago
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A wheelbarrow is experiencing two forces. One is pushing 5 N to the east and the other 5 N in the exact opposite direction. What
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Assuming no other forces are acting on the wheelbarrow, it must be stationary.
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If a child starts from rest at point A and lands in the water at point B, a horizontal distance L = 2.52 m from the base of the
tamaranim1 [39]

Answer:

The height of the water slide is 0.878 m

Explanation:

Given that,

Distance = 2.52 m

Suppose Children slide down a friction less water slide that ends at a height of 1.80 m above the pool.

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Using equation of motion

s=ut+\dfrac{1}{2}gt^2

Put the value in the equation

1.80=0+\dfrac{1}{2}\times9.8\times t^2

t^2=\dfrac{1.80\times2}{9.8}

t=\sqrt{\dfrac{1.80\times2}{9.8}}

t=0.606\ sec

We need to calculate the velocity

Using formula of velocity

v = \dfrac{d}{t}

Put the value into the formula

v=\dfrac{2.52}{0.606}

v=4.15\ m/s

We need to calculate height

Using conservation of energy

\dfrac{1}{2}mv^2=mgh

h=\dfrac{v^2}{2g}

Put the value into the formula

h=\dfrac{4.15^2}{2\times9.8}

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Hence, The height of the water slide is 0.878 m.

4 0
2 years ago
1. When red light shines on a red rose, what color do you see? Do the leaves become
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This is hard sorry but I need to anwser
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A cat chases a mouse across a 1.2 m high table. The mouse steps out of the way, and the cat slides off the table and strikes the
Drupady [299]
The cat has two directions of motions:
The horizontal motion = Dx = 2.2 m
The vertical motion = Dy = -1.3 m (negative sign indicates that the cat is falling)
a = 9.8 m/sec^2
Vy = zero (since you are not moving up)

From the laws of motion:
<span>Dy = Vyt + 0.5ayt^2 
</span>-1.3 = 0(t) + 0.5(-9.8)t^2
<span>t = 0.52s
</span>
Then, again using the laws of motion (but for the horizontal direction this time)
Dx = Vxt 
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<span>Vx = 2.2/0.52 </span>
<span>= 4.23 m/s 
</span>
<span>Therefore the cat's speed when it slid off the table is 4.23 m/s horizontally.</span>



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