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4 years ago

Hydrogen is a liquid below what temperature?

Chemistry

2 answers:

TEA [102]4 years ago

7 0

Hydrogen is a liquid below -253 degrees C

user100 [1]4 years ago

5 0

Answer:

The hydrogen exist as a liquid at -253 degree C.

Explanation:

Hydrogen is found as a molecular form H2. In order to become liquid , it must be cooled below its critical temperature. It become liquid at -253 degree C or 423.17 degree F or 20.8 K.

So hydrogen become liquid at -253 degree Celsius.

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Given: There are 39.95 grams of Argon (39.95 g/1 mole) and one mole has a volume of 22.4 Liters (1 mole/22.4 L). What is the vol

marta [7]

Answer:

$V_2=19.23L$

Explanation:

Hello,

In this case, by using the Avogadro's law which allows us to understand the volume-moles behavior as a directly proportional relationship:

$\frac{V_2}{n_2} =\frac{V_1}{n_1}$

We can compute the volume of 34.3 g of argon by representing it in mole as shown below:

$n_1=1 mol\\\\n_2=34.3g*\frac{1mol}{39.95g} =0.859mol$

Thus, we find:

$V_2=\frac{V_1*n_2}{n_1}=\frac{22.4L*0.859mol}{1mol} \\\\V_2=19.23L$

Best regards.

6 0

3 years ago

How many neutrons are present in 1 atom of chlorine?

pav-90 [236]

The answer is A.18 let me know if you want an explanation

4 0

3 years ago

Read 2 more answers

The mass of an electron is close to: A. 0.00055u. B. 0.05u. C. 10-10 u. D. 0.0001u

Debora [2.8K]

Answer:

A. 0.0005u

Explanation:

The mass of an electron in amu = 9.1*10-311.66*10-27=0.0005u.

7 0

3 years ago

Read 2 more answers

An aluminum cup of 140 cm3 capacity is completely filled with glycerin at 20°C. How much glycerin will spill out of the cup if t

mel-nik [20]

Explanation:

The given data is as follows.

coefficient of volume expansion of glycerin ( $\beta$ ) = $5.1 \times 10^{-4} 1/^{o}C$

linear expansion coefficient of aluminum, $(\alpha_{A})$ = $23 \times 10^{-6} 1/^{o}C$

Volume = 100 $cm^{3}$

The increase in volume of the cup will be calculated as follows.

$\Delta V_{c} = V \times 3 \times \alpha \times \Delta T$

= $100 cm^{3} \times 3 \times 23 \times 10^{-6} \times (31 - 20)^{o}C$

= $75900 \times 10^{-6} cm^{3}$

= 0.0759 $cm^{3}$

Formula for increase in volume of glycerine is as follows.

$\Delta V_{g} = V \times \beta_{g} \times \Delta T$

= $100 cm^{3} \times 5.1 \times 10^{-4} 1/^{o}C \times (31 - 20)^{o}C$

= 0.5610 $cm^{3}$

Therefore, volume of glycerin spilled is calculated as follows.

$\Delta V = \Delta V_{g} - \Delta V_{c}$

= (0.5610 - 0.0759) $cm^{3}$

= 0.4851 $cm^{3}$

Thus, we can conclude that 0.4851 $cm^{3}$ glycerin will spill out of the cup.

6 0

3 years ago

Determina la masa atómica promedio del cobre teniendo en cuenta que este elemento se encuentra en la naturaleza en forma de dos

beks73 [17]

Answer:

63.5474U.M.A. es la masa atómica promedio del cobre

Explanation:

La masa atómica promedio de un átomo es definida como la suma de las masas de los isótopos multiplicada por su abundancia. Para el caso del cobre que tiene dos isótopos:

Cu = Masa 65Cu*Abundancia + Masa 63Cu*Abundancia

Reemplazando con los valores dados en el problema:

Cu = 62.9298U.M.A.*0.6909 + 64.9278U.M.A.*0.3091

Cu = 63.5474U.M.A. es la masa atómica promedio del cobre

6 0

3 years ago