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3 years ago

Can someone finish this Punnett square please

Chemistry

1 answer:

soldier1979 [14.2K]3 years ago

4 0

Lower case t in the first 2 left boxes upper case in the other two

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What is the charge of the nucleus in boron

Reptile [31]

Answer:

Boron atoms lie in hexagonal aromatic graphite-like layers, with a charge of −1 on each boron atom. Magnesium (II) ions lie between layers Binary metal-boron compounds, the metal borides, contain boron in negative oxidation states. Illustrative is magnesium diboride (MgB 2).

Explanation:

8 0

3 years ago

A sample of raw mining ore contains a hydrated salt called copper sulfate tetrahydrate, CuSO4.4H2O, along with other impurities.

julsineya [31]

Answer:

88.5 % of the raw ore is CuSO4*4H2O

Explanation:

Step 1: Data given

Mass of the ore = 10.854 grams

Mass of water = 2.994 grams

Step 2: Calculate moles H2O

Moles H2O = mass H2O / molar mass H2O

Moles H2O = 2.994 grams / 18.02 g/mol

Moles H2O = 0.166 moles

Step 3: Calculate moles CuSO4*4H2O

For 1 mol CuSO4*4H2O we have 4 moles H2O

For 0.166 moles H2O we have 0.166/4 = 0.0415 moles CuSO4*4H2O

Step 4: Calculate mass CuSO4*4H2O

Mass CuSO4*4H2O = moles * molar mass

Mass CusO4*4H2O = 0.0415 moles * 231.67 g/mol

Mass CuSO4*4H2O = 9.61 grams

Step 5: Calculate mass % of CuSO4*4H2O

Mass % = (9.61 grams / 10.854 grams )*100 %

Mass % = 88.5 %

88.5 % of the raw ore is CuSO4*4H2O

4 0

4 years ago

How is an ionic compound formed

gladu [14]

Ionic compounds are formed when the transfer of electrons is a metal and non metal.<span />

8 0

4 years ago

Chemistry Help:

Umnica [9.8K]

It's answer A!
Reactants on left (see on the arrow), products on right.

7 0

3 years ago

A certain reaction has an enthalpy of Δ=44 kJ and an activation energy of a=61 kJ. What is the activation energy of the reverse

avanturin [10]

Answer:

E = 17 kJ

Explanation:

The enthalpy of the reaction is:

$\Delta H = E_{p} - E_{r}$

<u>Where</u>:

Ep: is the energy of the products

Er: is the energy of the reactants

Similarly, the enthalpy of the reaction is related to the activation energy forward ( $E_{F}$ ) and to the activation energy reverse ( $E_{R}$ ) as follows:

$\Delta H = E_{F} - E_{R}$

Having that ΔH = 44 kJ and $E_{F}$ = 61 kJ, the activation energy of the reverse reaction is:

$E_{R} = E_{F} - \Delta H = 61 kJ - 44 kJ = 17 kJ$

Therefore, the activation energy of the reverse reaction is 17 kJ.

I hope it helps you!

3 0

3 years ago