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vampirchik [111]
3 years ago
6

You put $600 in a savings account. The account earns 6% simple interest per year. a. What is the interest earned after 10 years?

The interest earned is $ after 10 years. b. What is the balance after 10 years? The balance is $ after 10 years.
HELP PLZ I WILL MARK AS BRAINLIEST
Mathematics
1 answer:
Lelu [443]3 years ago
7 0

Answer:

The answer is $960

Step-by-step explanation:

A = P(1 + rt)

[A] is Answer

[600] is P

[6%] is r

[10] is time

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Find the coordinates of the points of intersection of the graph of y=13−x with the axes and compute the area of the right triang
Ymorist [56]

the coordinates of the points of intersection of the graph of y=13−x with the axes

Given equation is y=13-x

x axis is x=0

y axis is y=0

Plug in the value of x =0 and find out y

y = 13 - x

y = 13 - 0 = 13

Plug in the value of y=0 and find out x

0 = 13 - x

x= 13

So coordinate axis

x= (13,0)

y= (0,13)

Base of the triangle is x=13

Height of the triangle is y= 13

Area of the triangle = \frac{1}{2} * base * height

= \frac{1}{2} * 13 * 13 = 84.5

Area of the triangle = 84.5


6 0
3 years ago
What is the value of the expression?<br> 2 1/4 divided by 1 2/5
ad-work [718]

Answer:

45/28

Step-by-step explanation:

Convert them to mixed fractions

(2 * 4 + 1) / 4 ÷ (1 * 5 + 2) / 5

8 + 1 / 4 ÷ 5 + 2 / 5

9/4 ÷ 7/5

Flip the second fraction and flip the sign - to multiply.

9/4 × 5/7

9 × 5 = 45

4 × 7 = 28

45/28

This could be left as a fraction or converted to a number:

1.60714285714

4 0
3 years ago
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Plz help me get the answer to these
almond37 [142]
-7p^5 + 5q + 5p^5
-2p^5 + 5q
6 0
3 years ago
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Write a problem that uses a fraction greater than 1.
Likurg_2 [28]
36/6 * 59             36/6 = to 6
3 0
3 years ago
8. H={all numbers of the form 3n+1, for n a natural number} under multiplication?
poizon [28]

Answer and Step-by-step explanation:

H= {all numbers of the form 3n+1, for n natural number} under multiplication:

Sol: all number of the form 3n+1, for n natural number so, put n=2, 3(2) +1 = 7, which is a natural number. A natural number under multiplication does not form a group because its inverse does not exist.

J= {all number of the form 3n+2, for n natural number} under multiplication:

Sol: all the number of the form 3n+2, n is the natural number does not form a group under multiplication because the identity element does not form in this set, and inverse does not exist.

K= {perfect squares of integers} under addition:

Sol: perfect square of integers under addition does not form a group because the inverse does not exist. For example, for any element x, inverse (-x) does not exist because of a square integer.

L= {perfect squares of integers} under multiplication:

Sol: a set of the perfect square of integers under multiplication is not a set, because it does not have the inverse property

M= {all numbers of the form 2, for n natural number} under addition:

Sol: natural number in the form of 2n, n is a natural number under addition is not a group as it does not have identity property. Identity property, under addition, is zero.

N= {all number of the form 2n, n is natural number} under multiplication:

All number of the form 2n, n is the natural number under multiplication is not a group. Because its inverse does not exist. For example, an element x belongs to a natural number; its inverse (1/x) does not exist in this set.

8 0
3 years ago
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