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IrinaVladis [17]
3 years ago
9

Thomas bought 7 dozen roses for the wedding. The roses were divided equally into 6 equal vases. How many roses are in each vase?

Mathematics
2 answers:
nalin [4]3 years ago
7 0
7 times 12 = 84

84 divided by 6 = 14
dlinn [17]3 years ago
5 0
There are 14 roses in each vase.
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The length of a rectangle is x feet. Its width is (x-7) feet. Draw and label a rectangle to represent this situation. Then write
a_sh-v [17]

Answer:

Perimeter of rectangle:

(4x - 14)\text{ feet}            

Step-by-step explanation:

We are given the following in the question:

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Width of rectangle:

(x-7)\text{ feet}

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Expressions to calculate perimeter

1. ~2((x) + (x - 7))\text{ feet}\\2.~2(2x-7)\text{ feet}\\3.~ 4x-14\text{ feet}

The attached image shows the image of the rectangle.

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Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments
kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

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\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

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arlik [135]

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