Answer:
x = 0
y = 1
Step-by-step explanation:
y = 4x + 1 -------eqn 1
y = x + 1 -------eqn 2
Looking for x, let's use eqn 1
y = 4x + 1
4x = y - 1
Divide both sides by 4, to get x
4x/4 = (y - 1) / 4
x = (y - 1) / 4
Substitute the value of x into eqn 2
y = x + 1
y = (y - 1) / 4 + 1
LCM = 4
y =( y - 1 + 4)/4
y =( y + 3) / 4
Cross multiply
y * 4 = y + 3
4y = y + 3
4y - y = 3
3y = 3
Divide both sides by 3, to get y
3y / 3 = 3/3
y = 1
Substitute y = 1 , into eqn 1
y = 4x + 1
1 = 4x + 1
1 -1 = 4x
0 = 4x
Divide both sides by 4, to get x
0/4 = 4x/4
0 = x
x = 0
Hint, let's check if the values are correct
Let's pick eqn 2
y = x + 1
y = 1
x = 0
1 = 0 + 1
1 = 1
Correct
Let's try the eqn 1
y = 4x + 1
1 = 4(0) + 1
1 = 0 + 1
1 = 1
Correct too