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MAXImum [283]
4 years ago
5

Need help!!! Physics due tomorrow help, help ,help

Physics
1 answer:
Sergio [31]4 years ago
7 0

1. Due to the first law of Newton: there is a force that accelerate the body,

then the net force for 2 forces in opposite directions can calculated as

F_{net}=F_{1}-F_{2}=26-8=14N

2. For a force make an angle with the horizontal plane, we need to analysis the force into 2 perpendicular forces:

- In horizontal plane:

F_{x}=Fsin ( θ )= 67sin(73)=64N

then, as Q(1),

F_{net}=F_{1}-F_{2}=64-33=31 N

3. Because of the non change in the velocity, there is no acceleration

Then, there is no force is acted from the body

Hence all forces is according to the tension in the cable

F_{Tension}=420 N

4. A) As we solve the Q(2), we will analysis the un horizontal or vertical forces into 2 forces

F_{x}=Fsin ( θ )= 600sin(45)=424.264N

F_{y} = F sin ( θ )= 600cos45)=424.264N

Hence we have 2 opposite horizontal forces. also, 2 opposite vertical forces.

now, we calculate the net forces in each direction

F_{net in x}=F_{1}-F_{2}=424.264-250=174.264 N in east

F_{net in y}=F_{1}-F_{2}=-500-424.264=75.736 N in south

The total net force for perpendicular forces is calculated from the relation:  

F_{total}=\sqrt{F_{x} ^{2}+F_{y}^{2}}=\sqrt{174.264^{2}+75.736^{2}}=190N

B) To find the direction, we need to calculate the angle which the total force is made with the east direction of the x-axis (horizontal)

θ = tan^{-1}(\frac{F_{y}}{F_{x} })= tan^{-1}(\frac{-75.736}{174.264})=-23.48^{o}

That meas that the total force is made with the east direction of the x-axis angle equal to 23.48 for the south (the 4th quarter)

5. According to the third law of Newton, to make the balance the net force  equal to zero (for each action there is a reaction with the same amplitude and in opposite direction)

Then, F_{right}=F_{left}=55N

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likoan [24]

Answer:

   V₂  = 46.99 μL.

Explanation:

Given that

V₁ = 45.1 μL

T₁ = 24.7°C  = 273 + 24.7 = 297.7 K

T₂ = 37.2°C = 273+37.2=310.2 K

Lets take  ,The final volume = V₂  

We know that ,the ideal gas equation  

If the pressure of the gas is constant ,then we can say that

\dfrac{V_2}{V_1}=\dfrac{T_2}{T_1}

{V_2}=V_1\times \dfrac{T_2}{T_1}

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7 0
3 years ago
jack be nimble jack be quick jack jumped over the candlestick with a velocity of 5.0 m/s at an angle of 30.0 degrees to horizont
Mrrafil [7]

Answer:

No

Explanation:

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5.0

⋅

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∘

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2.5

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0.255

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The average vertical component of his velocity in that

0.255

s

will be:

1

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⋅

2.5

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1.25

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So the highest point of his trajectory will be:

0.255

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1.25

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0.32

m

So he will pass approximately

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cm

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The horizontal component of his velocity will be a constant:

5.0

⋅

cos

30

∘

=

5.0

⋅

√

3

2

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4.33

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So Jack's trajectory will be substantially longer than it is high and he will spend little time anywhere near above the candle.

4 0
3 years ago
A carnival ride has a 2.0m radius and rotates once each .90s. Find the centripetal acceleration
Paraphin [41]
We know that centripetal acceleration is nothing but the ratio of the square of the tangential velocity to that of the radius vector.
a=v*v/r=ωωrr/r
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3 0
3 years ago
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Answer:

5s

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T=t/1c\\\\=5s/1\\\\=5s

Hence, the period of the pendulum is 5s

8 0
4 years ago
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Irina18 [472]
It looks correct, but that graph only shows position and time?
5 0
3 years ago
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