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valentina_108 [34]
3 years ago
12

Which of these values is equivalent to the change in momentum of

Physics
2 answers:
sasho [114]3 years ago
6 0

Answer : The correct option is, (A) impulse

Explanation :

Change in momentum : It is the product of the mass of an object and the change in velocity of an object.

Formula : \Delta p=m\times \Delta V

Impulse : It is the product of the force applied on the object and the time. It is also equivalent to the change in momentum of  an object.

Formula : J=F\times t

And the impulse is also equal to the change in momentum.

Proof of J=\Delta p :

J=F\times t\\\\J=(m\times a)\times t\\\\J=m\times (a\times t)\\\\J=m\times \Delta v=\Delta p

Force : It is the product of mass of an object and acceleration of an object.

Velocity : It is defined as the change in the position of an object in unit time.

Acceleration : It is defined as the change in the velocity of an object in a unit time.

Hence, the impulse is equivalent to the change in momentum of  an object.

iragen [17]3 years ago
3 0
<span>A. An impulse of a force changes the momentum of a body and has the same units and dimensions as momentum.</span>
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100 + 50 + BRAINLIST PLEASE HELP!!!
irina1246 [14]

Answer:

Explanation:

1. What are the forces acting on the block when it is hanging freely from the spring scale? What is the net force on the block? What are the magnitudes of each of the forces acting on the block? Explain.

When a block is hanging freely, two forces are acting on it = tension force from the spring scale and gravity force on the block itself. The net force is zero as the block is not accelerating.  The magnitudes of tension and gravity force are the same but in opposite directions.

2. What are the forces that act on the block when it is placed on the ramp and is held in place by the spring scale? What is the net force acting on the block? Explain. (Assume that the ramps are frictionless surfaces.)

There are three forces acting on the block when it is placed on the ramp and is held in place by the spring scale: as in 1, there are tension and gravity but there is a third force - reaction force from the ramp surface on the block that is perpendicular to the surface. Again the block is not moving so the net force is zero.

3. What is the magnitude of normal force acting on the block when it is resting on the flat surface? How does the normal force change as the angle of the ramp increases? Explain. (Assume that the ramps are frictionless surfaces.)

On flat surface, the normal force is equal to the gravity force of the block i.e. its weight. On a vertical surface, the normal force is equal to zero. For the angle of ramp, θ, the normal force = weight * cos θ.

6 0
3 years ago
Read 2 more answers
Describe the difference between global knowledge and personal ideas.
iren2701 [21]

Answer:

Global knowledge is information that is widely accepted and been proven as the truth. It is information that may not necessarily have a source because it is common knowledge and not easily attributed to a certain source. Personal ideas are original to the author and may not be widely accepted. It is important to give credit to others by citing their work to acknowledge that this is not your own findings but rather someone else's. It is plagiarism to use someone else's work as your own without giving credit to their work. -W0lf93

Explanation:

hope this helps

7 0
2 years ago
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Use the law of universal gravitacion to predict what would happen to Earth if the moon were replaced with an object that had the
Zina [86]
Verrrrry interesting !
If the moon were replaced by something with a vastly greater mass
but at the same distance, then ...

-- The period of its revolution around the Earth would be much shorter.
That is, it would orbit the Earth in much less than 27.3 days.  We might
see it go through a complete set of phases in 2 weeks, or even 1 week.

-- The ocean tides would be much greater.  Low tides would be
much lower, and high tides would be much higher.

-- Sadly, the land tides, and the forces on the Earth's internal structure,
would also be much greater.  That means great increases in earthquake
and volcanic activity.

-- The Earth and moon both revolve around their common center of
mass. Under the current arrangement ... with the Earth having 80 times
the mass of the Moon ... that point is inside the Earth, and it looks a lot
like the Moon is orbiting a stationary Earth.
When the new body arrives to replace the lightweight Moon, that point
will be a lot closer to the new companion ... maybe even inside it. 
Then, it will look a lot like the monster is the stationary one, and the
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I actually don't believe that we would SEE that change, or feel it.

8 0
3 years ago
A brass rod with a length of 1.22 m and a cross-sectional area of 2.19 cm2 is fastened end to end to a nickel rod with length L
GaryK [48]

Answer:

a) L₂ = 0.676 m

b) σ₁ = 2.28*10⁸ N/m²

σ₂ = 9.62*10⁸ N/m²

c) ε₁ = 0.00253678

ε₂ = 0.00457875

Explanation:

Given info

L₁ = 1.22 m

A₁ = 2.19 cm² = 2.19*10⁻⁴ m²

L₂ = ?

A₂ = 0.52 cm² = 0.52*10⁻⁴ m²

P = 5.00*10⁴ N

E₁ = 9*10¹⁰ N/m²

E₂ = 2.1*10¹¹ N/m²

In order to get the length L of the nickel rod if the elongations of the two rods are equal, we can say that

ΔL₁ = ΔL₂   ⇒  P*L₁/(A₁*E₁) = P*L₂/(A₂*E₂)

⇒  L₂ = A₂*E₂*L₁ / (A₁*E₁)

⇒  L₂ = (0.52*10⁻⁴ m²)*(2.1*10¹¹ N/m²)*(1.22 m) / (2.19*10⁻⁴ m²*9*10¹⁰ N/m²)

⇒  L₂ = 0.676 m

The stress in the brass rod is obtained as follows

σ₁ = P/A₁ ⇒ σ = 5.00*10⁴ N / 2.19*10⁻⁴ m² = 2.28*10⁸ N/m²

The stress in the niquel rod is obtained as follows

σ₂ = P/A₂ ⇒ σ = 5.00*10⁴ N / 0.52*10⁻⁴ m² = 9.62*10⁸ N/m²

The strain in the brass rod is obtained as follows

σ₁ = E₁*ε₁    ⇒   ε₁ = σ₁ / E₁

⇒   ε₁ = 2.28*10⁸ N/m² / 9*10¹⁰ N/m² = 0.00253678

The strain in the niquel rod is obtained as follows

σ₂ = E₂*ε₂    ⇒   ε₂ = σ₂ / E₂

⇒   ε₂ = 9.62*10⁸ N/m² / 2.1*10¹¹ N/m² = 0.00457875

3 0
2 years ago
A flux density of 1.2Wb/m^2 is required in the 1 mm air gap of an electromagnet having an iron path of length 1.5 m. Calculate t
Mandarinka [93]

Answer:

The mmf required is 1.125×10^{-3} A

Explanation:

The Magnetomotive force (mmf) is given by the formula below

F_{M} = Hl\\

where F_{M} is the Magnetomotive force (mmf)

H is the Magnetic field strength

l is the magnetic length

The magnetic permeability μ is given by

μ = B / H

Where B is the Magnetic flux density

and H is the Magnetic field strength

From the question,

B = 1.2Wb/m^2

μ = 1600m

From μ = B / H

∴H = B/μ

H = 1.2 / 1600\\

H = 7.5 × 10^{-4}A/m

Now, for the Magnetomotive force (mmf)

F_{M} = Hl\\

From the question

l = 1.5 m

∴ F_{M} = 7.5×10^{-4} × 1.5

F_{M} = 1.125×10^{-3} A

Hence, The mmf required is 1.125×10^{-3} A

3 0
3 years ago
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