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3 years ago

Which of these values is equivalent to the change in momentum of

Physics

2 answers:

sasho [114]3 years ago

6 0

Answer : The correct option is, (A) impulse

Explanation :

Change in momentum : It is the product of the mass of an object and the change in velocity of an object.

Formula : $\Delta p=m\times \Delta V$

Impulse : It is the product of the force applied on the object and the time. It is also equivalent to the change in momentum of an object.

Formula : $J=F\times t$

And the impulse is also equal to the change in momentum.

Proof of $J=\Delta p$ :

$J=F\times t\\\\J=(m\times a)\times t\\\\J=m\times (a\times t)\\\\J=m\times \Delta v=\Delta p$

Force : It is the product of mass of an object and acceleration of an object.

Velocity : It is defined as the change in the position of an object in unit time.

Acceleration : It is defined as the change in the velocity of an object in a unit time.

Hence, the impulse is equivalent to the change in momentum of an object.

iragen [17]3 years ago

3 0

A. An impulse of a force changes the momentum of a body and has the same units and dimensions as momentum.

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2 years ago

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Answer:

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2 years ago

A 0.29 kg particle moves in an xy plane according to x(t) = - 19 + 1 t - 3 t3 and y(t) = 20 + 7 t - 9 t2, with x and y in meters

Artist 52 [7]

Answer:

Part a)

$F = 7.76 N$

Part b)

$\theta = -137.7 degree$

Part c)

$\theta = -127.7 degree$

Explanation:

As we know that acceleration is rate of change in velocity of the object

So here we know that

$x = -19 + t - 3t^3$

$y = 20 + 7t - 9t^2$

Part a)

differentiate x and y two times with respect to time to find the acceleration

$a_x = \frac{d^2}{dt^2}(-19 + t - 3t^3)$

$a_x = \frac{d}{dt}(0 +1 - 9t^2)$

$a_x = -18t$

$a_y = \frac{d^2}{dt^2}(20 + 7t - 9t^2)$

$a_y = \frac{d}{dt}(0 +7 - 18t)$

$a_y = -18$

Now the acceleration of the object is given as

$\vec a = (-18t)\hat i + (-18)\hat j$

at t= 1.1 s we have

$\vec a = -19.8 \hat i - 18 \hat j$

now the net force of the object is given as

$\vec F = m\vec a$

$\vec F = (0.29 kg)(-19.8 \hat i - 18 \hat j)$

$\vec F = -5.74 \hat i - 5.22 \hat j$

now magnitude of the force will be

$F = \sqrt{5.74^2 + 5.22^2} = 7.76 N$

Part b)

Direction of the force is given as

$tan\theta = \frac{F_y}{F_x}$

$tan\theta = \frac{-5.22}{-5.74}$

$\theta = -137.7 degree$

Part c)

For velocity of the particle we have

$v_x = \frac{dx}[dt}$

$v_x = (0 +1 - 9t^2)$

$v_y = \frac{dy}{dt}$

$v_y = (0 +7 - 18t)$

now at t = 1.1 s

$\vec v = -9.89\hat i - 12.8 \hat j$

now the direction of the velocity is given as

$\theta = tan^{-1}(\frac{v_y}{v_x})$

$\theta = tan^{-1}(\frac{-12.8}{-9.89})$

$\theta = -127.7 degree$

7 0

3 years ago

The dimensions of the disk of our milky way galaxy are:.

Katen [24]

Answer:

According to studies, the milky way is approximately, "170,000–200,000 light-years (52–61 kpc) in diameter and, on average, approximately 1,000 ly (0.3 kpc) thick."

With that being said, it is safe to say that the dimensions are somewhere around 100,000 by 1,000

6 0

2 years ago

an engine has been design to work between source and the sink at temperature 177 degree Celsius and 27 degree Celsius respective

irina [24]

Given data

Source temperature (T₁) = 177°C = 177+273 = 450 K

Sink temperature (T₂) = 27°C = 27+273 = 300 K

Energy input (Q₁) = 3600 J ,

Work done = ?

We know that, efficiency (η) = Net work done ÷ Heat supplied

η = W ÷ Q₁

W = η × Q₁

First determine the efficiency ( η ) = ?

Also, we know that ( η ) = (T₁ - T₂) ÷ (T₁)

= 33.3% = 0.333

Now, Work done is W = η × Q₁

= 0.33 × 3600

W = 1188 J

Work done by the engine is 1188 J

4 0

3 years ago