10) A 50 gram sample of a material requires 660 J of heat to have its temperature
1 answer:
Specific heat of the material thus calculated is 0.22 J/ g °C
<u>Explanation</u>:
Given:
Mass of the sample (m) = 50g
Heat energy = Q = 660 J
Temperature get raised from 20° C to 80° C
To Find:
Specific Heat of the material.
Formula to be used:
Q = m×C×ΔT
where we know that,
Heat energy = Q = 660 J
Mass = m = 50 g
ΔT = 80 - 20 = 60° C
Now to calculate the specific heat of the material (c) we must substitute all the values, Then we get,
Thus the Specific heat of the material is 0.22 J/ g °C.
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Answer:
E. Student 1 is correct, because as θ is increased, h is the same.
Explanation:
Here we have the object of a certain mass falling under gravity so the force acting on the it will depend on mass of the object and the acceleration due to gravity.
Mathematically:
As we know that the work done is evaluated as the force applied on a body and the displacement of the body in the direction of the force.
And for work we have:
where:
displacement of the object
angle between the force and displacement vectors
Given that the height of the object is same in each trail of falling object under the gravity be it a free-fall or the incline plane.
- In case of free-fall the angle between the force is and the displacement is zero.
- In case when the body moves along the inclined plane the force applied by the gravity is same because it depends upon the mass of the object. And the net displacement in the direction of the gravitational force is the height of the object which is constant in both the cases.
So, the work done by the gravitational force is same in the two cases.