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kirill [66]
4 years ago
15

A cyclist rode at an average speed of 15mph for 30 miles how long was the ride

Physics
1 answer:
deff fn [24]4 years ago
6 0
2 hours because 15 miles is one hour and the trip was 30 miles. 30 divided by 15 is 2.
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If an object moving at 5 m/s accelerates for 30 seconds at a rate of 2
klasskru [66]

Answer:

V=u + at

V= final velocity

U= Initial velocity

a= acceleration

t= time taken

V= 5 + 30*2

V=5+60

V=65m/s

Explanation:

4 0
3 years ago
A 5.2 cm diameter circular loop of wire is in a 1.35 T magnetic field. The loop is removed from the field in 0.29 sec. Assume th
Katyanochek1 [597]

Answer:

9.88 milivolt

Explanation:

Given: diameter d = 5.2 cm

magnetic field B_1 = 1.35 T, final magnetic field B_2 =0 T

t = 0.29 sec.

we know emf =  - dΦ/dt

and flux Φ = BA

A= area

therefore emf ε = -A(B_2-B_1)/Δt

=-\pi(d/2)^2\frac{B_2-B_1}{\Delta t} \\=-\pi(0.052/2)^2\frac{0-1.35}{0.29} \\=98.8\times10^4\\=9.88 mV

3 0
3 years ago
A radio technician measures the frequency of an AM radio transmitter. The frequency is . What is the frequency in megahertz? Wri
sukhopar [10]

Complete Question

A radio technician measures the frequency of an AM radio transmitter. The frequency is 14603 kHz . What is the frequency in megahertz? Write your answer as a decimal.

Answer:

The value is  x =  14.6 \  MHz

Explanation:

From the question we are told that

  The  frequency is  f =  14603  \  kHz = 14603 *1000 = 14603000 \ Hz

Generally  

       1 Hz \to  1.0 *10^{-6} \  MHz

       14603000 \ Hz  \to x MHz

=>   x =  \frac{14603000 *  1.0*10^{-6}}{1 }

=>    x =  14.6 \  MHz

8 0
3 years ago
Certain neutron stars (extremely dense stars) are believed to be rotating at about 10 rev/s. If such a star has a radius of 18 k
Aleks [24]

Answer:

mass of the neutron star =3.45185×10^26 Kg

Explanation:

When the neutron star rotates rapidly, a material on its surface to remain in place, the magnitude of the gravitational acceleration on the central material must be equal to magnitude of the centripetal acc. of the rotating star.

That is

\frac{GM_{ns}}{R^2}= \omega^2 R

M_ns = mass odf the netron star.

G= gravitational constant = 6.67×10^{-11}

R= radius of the star = 18×10^3 m

ω = 10 rev/sec = 20π rads/sec

therefore,

M_{ns}= \frac{\omega^2R^3}{G} = \frac{4\pi^2\times(18\times10^3)^3}{6.67\times10^{-11}}

= 3.45185... E26 Kg

= 3.45185×10^26 Kg

4 0
3 years ago
SUB TO YFBG JAY ON YT RN ASAP
Svet_ta [14]
Oki said he would not hood him to go on a bike but i said he would be ok if you don’t have a ride home with you and green one for a
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