The less mass an object has, the --- its gravitational f
1 answer:
Answer:
<em>The less mass an object has, the </em><u>less</u><em> its gravitational [force.]</em>
Explanation:
Newton's Law of Gravity states that . The two <em>m</em> values are the objects' masses, G is the gravitational constant, and <em>r</em> is the distance between the objects' centers. Notice how the mass values are in the fraction's <em>numerator</em>? That means <em>increasing</em> the mass of one or both objects <em>increases</em>
. That also implies the inverse; <em>decreasing</em> the mass of one or both objects <em>decreases</em>
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The acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.
The given parameters;
- mass of the car, m = 1400 kg
- Initial velocity of the car, u = 25 m/s
- coefficient of kinetic friction, μ = 0.7
The acceleration of the car is calculated as follows;
a = μg
a = 0.7 x 9.8
a = 6.86 m/s²
The time taken for the car to stop is calculated by using Newton's second law of motion;
F = ma
Thus, the acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.
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Answer:
magnitude = 3
unit vector =
Explanation:
Given vectors:
u = 2i + 2j - k
v = -i + k = -i + 0j + k
(a) u x v is the cross product of u and v, and is given by;
u x v = i(2+0) - j(2 - 1) + k(0 - 2)
u x v = 2i - j - 2k
Now the magnitude of u x v is calculated as follows:
| u x v | =
| u x v | =
| u x v | =
| u x v | = 3
Therefore, the magnitude of u x v is 3
(b) The unit vector û parallel to u x v in the direction of u x v is given by the ratio of u x v and the magnitude of u x v. i.e
û =
u x v = 2i - j - 2k [<em>calculated in (a) above</em>]
|u x v| = 3 [<em>calculated in (a) above</em>]
∴ û =
∴ û =