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liberstina [14]
3 years ago
11

The less mass an object has, the --- its gravitational f

Physics
1 answer:
BaLLatris [955]3 years ago
4 0

Answer:

<em>The less mass an object has, the </em><u>less</u><em> its gravitational  [force.]</em>

Explanation:

Newton's Law of Gravity states that F_G=\frac{Gm_1m_2}{r^{2}}. The two <em>m</em> values are the objects' masses, G is the gravitational constant, and <em>r</em> is the distance between the objects' centers. Notice how the mass values are in the fraction's <em>numerator</em>? That means <em>increasing</em> the mass of one or both objects <em>increases</em> F_G. That also implies the inverse; <em>decreasing</em> the mass of one or both objects <em>decreases</em> F_G!

I hope this helps you understand this concept a little more! Have yourself a fantastic day, 'kay?

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A solid conducting sphere has net positive charge and radiusR = 0.600 m . At a point 1.20 m from the center of the sphere, the e
gayaneshka [121]

Answer:

  V_inside = 36 V

Explanation:

<u>Given  </u>

We are given a sphere with a positive charge q with radius R = 0.400 m Also, the potential due to this charge at distance r = 1.20 m is V = 24.0 V.  

<u>Required</u>

We are asked to calculate the potential at the centre of the sphere  

<u>Solution</u>

The potential energy due to the sphere is given by equation

V = (1/4*π*∈o) × (q/r)                                          (1)

Where r is the distance where the potential is measured, it may be inside the sphere or outside the sphere. As shown by equation (1) the potential inversely proportional to the distance V  

V ∝ 1/r

The potential at the centre of the sphere depends on the radius R where the potential is the same for the entire sphere. As the charge q is the same and the term (1/4*π*∈o) is constant we could express a relation between the states , e inside the sphere and outside the sphere as next

V_1/V_2=r_2/r_1

V_inside/V_outside = r/R

V_inside = (r/R)*V_outside                               (2)

Now we can plug our values for r, R and V_outside into equation (2) to get  V_inside

V_inside = (1.2 m )/(0.600)*18

               = 36 V

  V_inside = 36 V

7 0
3 years ago
Read 2 more answers
On an icy road, a 1100 kg car moving at 55 km/h strikes a 480 kg truck moving in the same direction at 37 km/h . The pair is soo
statuscvo [17]

Answer:

Speed of the wreckage = 49.29 km/hr

Explanation:

This question is solved simply by using the conservation of momentum law.

The momentum of the three moving bodies are calculated below:

Momentum of Car 1 : 1100 * 55 = 60500 kg.km/hr

Momentum of Truck : 480 * 37 = 17760 kg.km/hr

Momentum of Car 2 : 1300 * 49 = 63700 kg.km/hr

Total mass of all three vehicles: 1100 + 480 + 1300 = 2880 kg

The final momentum equals the initial momentum if it is conserved. Thus we have the following equation:

Final Momentum = Initial Momentum

Final Velocity * Total mass = Momentum of all three vehicles combined

Final Velocity * 2880 = 60500 + 17760 + 63700

Final Velocity = 49.29 km/hr

7 0
4 years ago
Read 2 more answers
Why do naturalists suggest that we plant more trees?
____ [38]
The answer is so we have more oxygen and because loggers are cutting down more trees every day and the more they cut the less air we have
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4 years ago
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What is the gravitational potential energy of a rock with the mass of 67 kg if it is sitting on top of a hill .35 kilometers hig
solong [7]
Not to sure but maybe 23.45
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3 years ago
Sound is repeated near hills....<br>Why??? ​
madam [21]

Answer:

because there is many places for it to bounce of of creating another soundwave

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