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liberstina [14]
3 years ago
11

The less mass an object has, the --- its gravitational f

Physics
1 answer:
BaLLatris [955]3 years ago
4 0

Answer:

<em>The less mass an object has, the </em><u>less</u><em> its gravitational  [force.]</em>

Explanation:

Newton's Law of Gravity states that F_G=\frac{Gm_1m_2}{r^{2}}. The two <em>m</em> values are the objects' masses, G is the gravitational constant, and <em>r</em> is the distance between the objects' centers. Notice how the mass values are in the fraction's <em>numerator</em>? That means <em>increasing</em> the mass of one or both objects <em>increases</em> F_G. That also implies the inverse; <em>decreasing</em> the mass of one or both objects <em>decreases</em> F_G!

I hope this helps you understand this concept a little more! Have yourself a fantastic day, 'kay?

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Ronch [10]

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3 0
3 years ago
Which are examples of a medium? water and air amplitude and wavelength crests and troughs compressions and rarefactions
umka21 [38]

Answer:

water and air

Explanation:

  • A wave is a transmission of a disturbance from one point or the source to another  point.
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6 0
3 years ago
Read 2 more answers
A rock is suspended by a light string. When the rock is in air, the tension in the string is 51.9 N . When the rock is totally i
Luden [163]

Answer:

\rho _{liquid}=1995.07kg/m^{3}

Explanation:

When the rock is immersed in unknown liquid the forces that act on it are shown as under

1) Tension T by the string

2) Weight W of the rock

3) Force of buoyancy due to displaced liquid B

For equilibrium we have T_{3}+B = W_{rock}

T_{3}+\rho _{Liquid}V_{rock}g=W_{rock}.....(\alpha)

When the rock is suspended in air for equilibrium we have

T_{1}=W_{rock}....(\beta)

When the rock is suspended in water for equilibrium we have

T_{2} + \rho _{water}V_{rock}g=W_{rock}.....(\gamma)

Using the given values of tension and solving α,β,γ simultaneously for \rho _{Liquid} we get

W_{rock}=51.9N\\31.6+1000\times V_{rock}\times g=51.9N\\\\11.4+\rho _{liquid}V_{rock}g=51.9N\\\\

Solving for density of liquid we get

\rho _{liquid}=\frac{51.9-11.4}{51.9-31.6}\times 1000

\rho _{liquid}=1995.07kg/m^{3}

5 0
3 years ago
Select the correct answer.
Yuliya22 [10]

Answer:

B.

Explanation:

7 0
3 years ago
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Newton's first law of motion is the law of inertia
saw5 [17]

Answer:

this statement is true because I looked it up

7 0
3 years ago
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