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3 years ago

E = mc to the second power and M = 3 and C = 6, but I need to solve for e

Mathematics

2 answers:

Snowcat [4.5K]3 years ago

7 0

E=3(6)^2
3(36)
=108

Therefore E=108

Westkost [7]3 years ago

6 0

E=108
M=3 times C^2=6^2
6^2=36
3 times 36=108

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Which of the following holds about 1 L of water

motikmotik

A liter jug of soda, duh. Pour the soda out, use the bottle, put water in it

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3 years ago

What are the next two numbers in the pattern 3,6,5,10,9,18,17.

LenKa [72]

This pattern appears to alternate between doubling and subtracting by 1.

To get from 3 to 6, we multiply by two.
To get from 6 to 5, we subtract one.
To get from 5 to 10, we multiply by two.
To get from 10 to 9, we subtract one.
To get from 9 to 18, we multiply by two.
To get from 18 to 17, we subtract one.

Therefore, next we need to multiply by two.
17 x 2 = 34
So, the next number is 34.

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Thus, the number after is 33.

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3 years ago

Read 2 more answers

Use the given conditions to write an equation for the line in point-slope form and general form. Passing through (8 comma negat

miskamm [114]

Answer:

The answer to your question is y = -5x + 32 point-slope form

5x + y - 32 = 0 general form

Step-by-step explanation:

Data

(8, -8)

⊥ x - 5y - 6 = 0

Process

1.- Get the slope of the line given

x - 5y - 6 = 0

-5y = -x + 6

y = -x/-5 + 6/-5

y = x/5 - 6/5

slope = 1/5

slope of the new line -5, because the lines are perpendicular

2.- Get the equation of the new line

y - y1 = m(x - x1)

y + 8 = -5(x - 8)

y + 8 = -5x + 40

y = -5x + 40 - 8

y = -5x + 32 point-slope form

Equal to zero to find the general form

5x + y - 32 = 0 general form

5 0

3 years ago

A person on tour has dollar 360 for his daily expenses. If he extends his tour for 4 days, he has to cut down his daily expenses

mash [69]

Answer:

The original duration of the tour = 20 days

Step-by-step explanation:

Solution:

Total expenses for the tour = $360

Let the original tour duration be for $x$ days.

So, for $x$ days the total expense = $360

Thus the daily expense in dollars can be given by = $\frac{360}{x}$

Tour extension and effect on daily expenses.

The tour is extended by 4 days.

Tour duration now = $(x+4)$ days

On extension, his daily expense is cut by $3

New daily expense in dollars = $(\frac{360}{x}-3)$

Total expense in dollars can now be given as: $(x+4)(\frac{360}{x}-3)$

Simplifying by using distribution (FOIL).

$(x.\frac{360}{x})+(x(-3)+(4.\frac{360}{x})+(4(-3))$

$360-3x+\frac{1440}{x}-12$

$348-3x+\frac{1440}{x}$

We know total expense remains the same which is = $360.

So, we have the equation as:

$348-3x+\frac{1440}{x}=360$

Multiplying each term with $x$ to remove fractions.

$348x-3x^2+1440=360x$

Subtracting $348x$ both sides

$348x-348x-3x^2+1440=360x-348x$

$-3x^2+1440=12x$

Dividing each term with -3.

$\frac{-3x^2}{-3}+\frac{1440}{-3}=\frac{12x}{-3}$

$x^2-480=-4x$

Adding $4x$ both sides.

$x^2+4x-480=-4x+4x$

$x^2+4x-480=0$

Solving using quadratic formula.

For a quadratic equation: $ax^2+bx+c=0$

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Plugging in values from the equation we got.

$x=\frac{-4\pm\sqrt{(4)^2-4(1)(-480)}}{2(1)}$

$x=\frac{-4\pm\sqrt{16+1920}}{2}$

$x=\frac{-4\pm\sqrt{1936}}{2}$

$x=\frac{-4\pm44}{2}$

So, we have

$x=\frac{-4+44}{2}$ and $x=\frac{-4-44}{2}$

$x=\frac{40}{2}$ and $x=\frac{-48}{2}$

∴ $x=20$ and $x=-24$

Since number of days cannot be negative, so we take $x=20$ as the solution for the equation.

Thus, the original duration of the tour = 20 days

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3 years ago

If ΔLMN ≅ ΔOPR, m∠L = (x^2 - x)°, m∠P = 16°, m∠N = (4x+160)°. Find m∠R.

Marizza181 [45]

Answer:

mZR = (4x + 160)°

Step-by-step explanation:

cause, mZR = mZN

;-))

8 0

3 years ago