This is a product of meiosis
The frequency <em>p</em> of the yellow (A) allele is <em>p</em>= 0.3
The frequency <em>q</em> of the blue (a) allele is <em>q= </em><em>0.7</em>
Hardy–Weinberg equilibrium, states that allele and genotype frequencies in a population will remain constant from generation to generation. Equilibrium is reached in the absence of selection, mutation, genetic drift and other forces and allele frequencies p and q are constant between generations. In the simplest case of a single locus with two alleles denoted A and a with frequencies f(A) = p and f(a) = q, the expected genotype frequencies under random mating are f(AA) = p² for the AA homozygotes, f(aa) = q² for the aa homozygotes, and f(Aa) = 2pq for the heterozygotes.
p²+2*p*q+q²= 1 p+q= 1 q= 1-p
yellow (p²)= 9%= 0.09 p= √0.09= 0.3
green (2*p*q)= 42%= 0.42
blue (q²)=49%= 0.49 q=1-0.3= 0.7 <em>or</em> q= √0.49= 0.7
Answer:
They tunnel through the soil, which allows air to enter.
Explanation:
Earthworms are considered to be agriculturally friendly living organisms that hold immense importance in improving the growth and productivity of plants.
They live in the soil and feed on the debris of plants such as manure, grasses, roots and dead leaves. They extensively channel and tunnel through soils while moving that causes loosening of the soil resulting in more aeration of the soil. The more the soil aeration is, the better soil drainage is.
Studies have shown that soil containing earthworms have ten times better drainage than soils that donot have earthworms. Therefore, C is the best option.
Hope it help!
Wind please tell me if it’s wrong or right and heart this if it is right please
