Question 1 is nucleolus and other chromatins (chromosomes), nuclear bodies, nuclear matrix, nucleoplasm, and nuclear envelope. Question 2 is Lysosomes are membrane-bound organelles found in every eukaryotic cell. They are widely known as terminal catabolic stations that rid cells of waste products and scavenge metabolic building blocks that sustain essential biosynthetic reactions during starvation.
The correct answer is 50%, or 1/2. We know that round seeds are dominant, since the round pea plant has a genotype of Rr and the wrinkled pea plant has a genotype of rr. If it helps, draw a Punnett square with the two genotypes.
R r
r
r
The square works exactly like a coordinate grid. Combine the letters above and beside whichever of the four spaces you chose to find the genotype for that space.
R r
r Rr rr
r Rr rr
Therefore, 2 out of 4 of the pea plants have round seeds, since a genotype of Rr means that a plant will have round seeds, and 2 out of 4 will have wrinkled seeds, since a genotype of rr means that a plant will have wrinkled seeds. 2/4 simplifies to 1/2, or 50%. Therefore, there is a 50% chance that the offspring will have wrinkled seeds.
Hope this helps!
I think it’s proteins and nucleic acids
Answer:
a. the virus must be able to cross-link red blood cells directly.
Explanation:
Viral hemagglutination assay is a method which is used for the quantification of the relative concentration of the viruses.
The principle on which the hemagglutination assay works is as follows:
- There are sialic acid receptors present on the surface of the red blood cells which will bind to the haemagglutinin glycoprotein present on the surface of the viral particle.
- Due to the binding of the sialic acid receptors with haemagglutinin particle there will be cross-linking of the red blood cells by the viral particles and a lattice formation will take place.
- The lattice will remain suspended in the solution however if the concentration of the virus particles will be less, the lattice will settle down in the well.
Thus, this method allows knowing the relative concentration of the virus.
<em>Due to its basic principle of cross-linking this method works well for only a few viruses such as influenza virus. </em>
