Which pair of equations are perpendicular lines?<br>

There is a 50$ fee to rent out a bouncy house, plus 20$ per hour.

nalin [4]

Answer:

1. $50+$20x

2. 3 hours

3. $170

Step-by-step explanation:

I am not gonna explain so, don't ask.

6 0

3 years ago

PLEASSE HEP MEEEEEEEE

DENIUS [597]

Answer:

s = 70

Step-by-step explanation:

$\frac{s}{10} = 7$

$10 \times \frac{s}{10} = 10 \times 7$

$s = 70$

<h2>Insta: 25k_kem</h2>

3 0

3 years ago

A box of 6 matchbox cars cost $11.94. How many matchbox cars are in a box that costs $27.86

VashaNatasha [74]

Answer:

14

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

So can someone explain how the heck does 4 x 4 x 4 = 64??

sweet-ann [11.9K]

Answer:

it is more like, 4x4=16

16x4=64

Step-by-step explanation:

I know it can be confusing, but you will eventually get it :)

i think you were adding 4+4+4=12, but that is not what you are supposed to do here.

Hope i helped :)

5 0

2 years ago

Suppose M is the midpoint of Segment AB, P is the midpoint of Segment AM, and Q is the midpoint of segment PM.

DerKrebs [107]

The coordinates of M, P and Q in terms of a and b are $M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b$ , $P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b$ and $Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b$ , respectively.

In this question we are going to use definitions of vectors and product of a vector by a scalar. Based on the information given on statement, we have the following vectorial formulas:

Location of M

$\overrightarrow{AM} = \frac{1}{2}\cdot \overrightarrow{AB}$

$\vec M - \vec A = \frac{1}{2}\cdot \vec B - \frac{1}{2}\cdot \vec A$

$\vec M = \frac{1}{2}\cdot \vec A +\frac{1}{2}\cdot \vec B$

$M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b$

Location of P

$\overrightarrow{AP} = \frac{1}{2}\cdot \overrightarrow{AM}$

$\vec P - \vec A = \frac{1}{2}\cdot \vec M - \frac{1}{2}\cdot \vec A$

$\vec P = \frac{1}{2}\cdot \vec A +\frac{1}{2}\cdot \vec M$

$\vec P = \frac{3}{4}\cdot \vec A + \frac{1}{4}\cdot \vec B$

$P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b$

Location of Q

$\overrightarrow{QM} = \frac{1}{2}\cdot \overrightarrow{PM}$

$\vec M - \vec Q = \frac{1}{2}\cdot \vec M - \frac{1}{2}\cdot \vec P$

$\vec Q = \frac{1}{2}\cdot \vec P - \frac{1}{2}\cdot \vec M$

$\vec Q = \frac{1}{2}\cdot \left(\frac{3}{4}\cdot \vec A + \frac{1}{4}\cdot \vec B\right) -\frac{1}{2}\cdot \left(\frac{1}{2}\cdot \vec A + \frac{1}{2}\cdot \vec B\right)$

$\vec Q = \frac{1}{8}\cdot \vec A -\frac{1}{8}\cdot \vec B$

$Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b$

The coordinates of M, P and Q in terms of a and b are $M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b$ , $P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b$ and $Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b$ , respectively.

We kindly invite to check this question on midpoints: brainly.com/question/4747771

4 0

2 years ago

Which pair of equations are perpendicular lines?​

Which pair of equations are perpendicular lines?