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kakasveta [241]
3 years ago
11

At room temperature iodine is a solid and bromine is a liquid.

Chemistry
1 answer:
vichka [17]3 years ago
3 0

Answer:

<u>Kinetic particle theory</u>

Arrangement and motion of solid particles

-> Solid particles are packed closely with each other in an orderly manner. They vibrate vigorously in their fixed positions.

Arrangement and motion of liquid particles

-> Liquid particles are packed less closely with each other as compared to solid particles in a disorderly manner. They move around in a random motion; sliding past each other.

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RoseWind [281]

Answer:

no. of moles = measured mass of substance/ molar mass of the constituted elements

Explanation:

No. of moles of 2.0g NaCl= 2/(23+35.5) = 0.034mol

3 0
3 years ago
Is 2 C4H10 + 13 O2 → 8 CO2 + 10 H2O a double replacement?
natulia [17]

Answer:

The answer to your question is No, it is not.

Explanation:

Data

                C₄H₁₀  +  13O₂   ⇒   8CO₂ +  10H₂O

In a double replacement reaction, two reactants interchange cations an example of these reactions are neutralization reactions. In neutralization reactions, an acid and a base react to form a salt and water.

The reaction of this problem is not a double replacement reaction because the products are carbon dioxide and water, not a salt and water.

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8 0
4 years ago
Animal communication includes _____.
rusak2 [61]

<em> </em><em>it's </em>

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6 0
3 years ago
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The stock concentration of NaOH is 0.5M. 0.5M = 0.500mol/1.0L.
valentinak56 [21]

Answer:a) 0.1 mole. b) 4g. c) 2% d)  196 mL

Explanation: in 200mL , 0.1mole

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density NaOH = 1g/mL so if 4g in 200 mL,  4mL , 196 mL water

5 0
3 years ago
What is the mass of an original 5.60-gram sample of iron-53 that remains unchanged after 25.53 minutes?
olga_2 [115]
Answer is 0.7 g

Reason: Given: mass of Fe = 5.60 gWe know that, half life of Fe-53 = t1/2 (Fe-53) = 8.51 min.
Thus, after 25.53 mins, number of half life passed = 25.53/8.51= 3

Now, Amount left after first half life = 5.60g/2 = 2.80 g
Amount left after second half life = 2.80g/2 = 1.40 g
Amount left after third half-life = 1.40g/2 = 0.7g.
4 0
4 years ago
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