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Gala2k [10]
3 years ago
15

All examples involve chemical energy except __________. A. working muscles using food. B. burning a candle. C. coasting downhill

on a bike
Physics
2 answers:
navik [9.2K]3 years ago
7 0
The one that does not involve chemical energy would be : C. Coasting downhill on a bike
This one requires physical energy, To be categorized as chemical energy, the bond of chemical compounds has to be released

Hope this helps
kompoz [17]3 years ago
7 0

Answer:

Coasting downhill on a bike

Explanation:

The example that involves chemical energy are working muscles using food and burning a candle. In both of these processes many biochemical processes are involved i.e. mobilization of energy from glucose stores etc.

Coasting downhill on a bike does not involve any chemical energy. There exists an energy change i.e. potential energy is converting to kinetic energy.

Hence, the correct option is (c) "coasting downhill on a bike".

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g You drop a 3.6-kg ball from a height of 3.5 m above one end of a uniform bar that pivots at its center. The bar has mass 9.9 k
Salsk061 [2.6K]

Answer:

h = 3.5 m

Explanation:

First, we will calculate the final speed of the ball when it collides with a seesaw. Using the third equation of motion:

2gh = v_f^2 - v_i^2\\

where,

g = acceleration due to gravity = 9.81 m/s²

h = height = 3.5 m

vf = final speed = ?

vi = initial speed = 0 m/s

Therefore,

(2)(9.81\ m/s^2)(3.5\ m) = v_f^2 - (0\ m/s)^2\\v_f = \sqrt{68.67\ m^2/s^2}\\v_f = 8.3\ m/s

Now, we will apply the law of conservation of momentum:

m_1v_1 = m_2v_2

where,

m₁ = mass of colliding ball = 3.6 kg

m₂ = mass of ball on the other end = 3.6 kg

v₁ = vf = final velocity of ball while collision = 8.3 m/s

v₂ = vi = initial velocity of other end ball = ?

Therefore,

(3.6\ kg)(8.3\ m/s)=(3.6\ kg)(v_i)\\v_i = 8.3\ m/s

Now, we again use the third equation of motion for the upward motion of the ball:

2gh = v_f^2 - v_i^2\\

where,

g = acceleration due to gravity = -9.81 m/s² (negative for upward motion)

h = height = ?

vf = final speed = 0 m/s

vi = initial speed = 8.3 m/s

Therefore,

(2)(9.81\ m/s^2)h = (0\ m/s)^2-(8.3\ m/s)^2\\

<u>h = 3.5 m</u>

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