All categories

2 years ago

What are the names of neptunes moons

Physics

1 answer:

alexandr402 [8]2 years ago

5 0

Answer:

1. naiad

2.Thalassa

3 Despina

4 Galatea

5 Larissa

6 Hippocamp

7 Proteus ˈ

8 Triton

9 Nereid

10 Halimede

11 Sao

12 Laomedeia

13 Psamathe

14 Neso

Explanation:

hope this helped

You might be interested in

Describing Energy Transformations

UNO [17]

Answer:

chemical energy to electrical energy to sound energy to heat energy

4 0

2 years ago

Monochromatic light of wavelength, lambda, is traveling in air. The light then strikes a thin film having an index of refraction

kumpel [21]

Answer:

The correct option is H

Explanation:

From the question we are told that

The index of refraction of coating is $n_1$

The index of refraction of material is $n_2$

Generally the condition for constructive for a thin film interference is mathematically represented

$2 * t = [ m + \frac{1}{2}] \frac{\lambda}{n_1 }$

Here t represents the thickness

For minimum thickness m = 0

$2 * t =0 + \frac{1}{2}\frac{\lambda}{n_1 }$

=> $t =\frac{\lambda}{4n_1 }$

3 0

2 years ago

A young woman walks up 55 steps to the top of a water slide. She slides

navik [9.2K]

Answer:

potential energy PE = M g h

KE at bottom = 1/2 M V^2

Regardless of the slope of the slide the change in energy is the same

1/2 V^2 = g h

V = (2 g h)^1/2 = (2 * 9.8 m/s^2 * 10 m)^1/2 = 14 m / s

Perhaps the question says that h = 55 * .1 = 5.5 m

Then V = (2 * 9.8 * 5.5) = 10.4 m/s

5 0

1 year ago

Cuanto es tres por dos más cinco<br>3 * 2 + 5 es igual

Simora [160]

Answer:

3×2+5=11

Explanation:

3×2+5=

6+5

4 0

2 years ago

One mole of a gas is placed in a closed system with a 20 L vessel initially at T = 300 K. The vessel is then isothermally expand

Elden [556K]

Answer:

Given that

P = RT/V + a/V²

We know that

H= U + PV

For T= Constant (ΔU=0)

ΔH= ΔU +Δ( PV)

ΔH= Δ( PV)

P = RT/V + a/V²

P V= RT + a/V

dH/dV = d(RT + a/V)/dV

dH/dV = - a/V²

So the expression of dH/dV

$\dfrac{dH}{dV}=\dfrac{-a}{V^2}$

In isothermal process

$\Delta H=nRT\ln{\dfrac{V_2}{V_1}}$ (ΔU=0)

Now by putting the all values

$\Delta H=nRT\ln{\dfrac{V_2}{V_1}}$

$\Delta H=1\times 0.08206\times 300\ln{\dfrac{40}{20}}$

ΔH = 17.06 L.atm

8 0

2 years ago