Answer:
the magnitude of the charge Q on each plate is 
Explanation:
Given that :
mass (m) = 
charge (q) = +0.155 µC = 
angle 
Area A on each plate = 0.0135 m²
From the diagram below;
----- equation (1)
Also by using Gauss Law ;
----- equation (2)
Combination equation 1 and 2 together ; we have
Answer:
a)
Weight in Air = 0.3N
Weight in Water = 0.25N
Weight in Liquid = 0.24N.
Upthrust /Buoyant Force = Weight in Air – Weight in Fluid(Water in this case)
= 0.3 – 0.25
= 0.5N.
b) R.D of Body = Density of Body/Density of Standard Fluid(Water).
There's a Derived Formula for RD.
I'm gonna Apply it here.
Ask me for the derivation in the Comment section if you need it.
RD = α/ρ = (Weight in Air) / (Upthrust Force)
Where
α = density of the Body(or reference substance)
ρ = density of standard fluid (water)
= 0.3/0.05 = 6.
c) RD of Liquid = (Density of Liquid) /(Density of standard Fluid(water)
Or we just go by that formula
RD of Liquid = Weight in Air/Upthrust(In Liquid)
We'll be using the Upthrust in that Liquid now.
= 0.3 – 0.24 = 0.06
RD = 0.3/0.06 = 5.
Answer:
someone that is disorderly or dirty
The process of determining the value of the individual forces acting upon an object involve an application of Newton's second law (Fnet<span>=m. a) and an application of the meaning of the </span>net force<span>.</span>
