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Shkiper50 [21]
3 years ago
8

If the absolute value of the price elasticity of demand for DVD movies is 0.8 then the elasticity of demand of the DVD for the m

ovie The Hangover should be
Physics
1 answer:
Natalka [10]3 years ago
5 0

Answer:

greater than 0.8 in absolute value

Explanation:

Price elasticity demand (PED) is a tool used in economics to show the responsiveness or elasticity of the quantity demanded of a good or service to increase in its price when nothing but the price changes. So if  the absolute value of the price elasticity of demand for DVD movies is 0.8 then the elasticity of demand of the DVD for the movie The Hangover should be greater than 0.8 in absolute value.

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Mass  = 1kg 
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Force= Mass x Acceleration due to graviy
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Velocity = Distance  / time
              = 1 / 1 =1m/s
Power = Force x velocity
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What is the relationship between the weight of objects and the sum of their parts?
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No matter how parts of an object are assembled, the weight of the whole object is always the same as the sum of the parts; and when a thing is broken into parts, the parts have the same total weight as the original thing.

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Step by step:

Use the law of energy conservation. When the elevator hits the spring, it has a certain kinetic and a potential energy. When the elevator reaches the point of still stand the kinetic and potential energies have been transformed to work performed by the elevator in the form of friction (brake clamp) and loading the spring.

Let us define the vertical height axis as having two points: h=2m at the point of elevator hitting the spring, and h=0m at the point of stopping.

The total energy at the point h=2m is:

E_{tot}=E_{kin}+E_{pot}\\E_{tot}= \frac{1}{2}mv^2+mg\Delta h = \frac{1}{2}2000 kg 4^2\frac{m^2}{s^2}+2000kg\, 9.8\frac{m}{s^2}2m=55200\,kg\frac{m^2}{s^2}

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E_{tot}=E_{kin}+E_{pot}+Work=0+0+ Work\\E_{tot} =F_{friction}\Delta h+\frac{1}{2}k (\Delta h)^2=17000N\cdot 2m+\frac{1}{2}k\cdot 2^2 m^2

The two Energy values are to be equal (by law of energy conservation), which allows us to determine the only unknown, namely the force constant k:

17000N\cdot 2m+\frac{1}{2}k\cdot 2^2 m^2 = 55200 \,kg\frac{m^2}{s^2}\\k = \frac{55200-34000}{2}\,\frac{kg}{s^2}=10600\frac{kg}{s^2}

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