Answer: D
Frequency = 587.32 Hz
Step-by-step explanation:
One octave above has a frequency of 2 × 146.83 Hz = 293.66Hz (D4). Two octaves above has afrequency of 2 × 293.66 Hz = 587.32 Hz (D5)
Given
Expenditures at Manager's Store; expenditures at Competitor's Store.
Find
a) average spent at each store
b) which store is better represented by the mean value
c) an explanation for the answer in ≥ 2 sentences
Solution
a) The sum of expenditures divided by the number of expenditures (15) is ...
... average for Manager's Store: $37.60
... average for Competitor's Store: $48.53
b) The expenditures at Manager's Store are well-represented by the mean (average).
c) The range of expenditures at Competitor's Store is significantly higher than at Manager's store, so a single number such as mean or median does not represent the data well. The expenditures at Manager's store are more compactly grouped around the mean and median, which are closer together, so the mean is a good representation of Manager's Store expenditures overall.
Answer...

Steps....
1) Rewrite the decimal number as a fraction with 1 in the denominator
2) Multiply to remove 4 decimal places. Here, you multiply top and bottom by
= 10000
3) Find the Greatest Common Factor (GCF) of 2800575 and 10000, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 25
4) Simplify the improper fraction!
Answer:
y>0
all positive real numbers
Step-by-step explanation:
the range is the output values
this will always be greater than 0
Range : y>0