All categories

4 years ago

A transverse wave is traveling on a string stretched along the horizontal x-axis. The equation for the

Physics

1 answer:

maxonik [38]4 years ago

6 0

Answer:

A) 0.33 m/s

Explanation:

The standard form of a transverse wave is given by

y = a cos ( ω t − kx ) , k = 2 π / λ

Amplitude, a = 0.002 m

Wavenumber (k)=47.12 and wavelength ( λ ) = 0.133 m

Time period(T)=0.0385 s and angular frequency ( ω ) = 52 π rad/s

Maximum speed of the string is given by aw

Therefore ; max. speed = 0.002 x 52 π = 0.327 m/s

You might be interested in

You decide to push on a brick wall with all your might for 5 minutes. You

Artist 52 [7]

Answer:

Explanation:W=F*S

W=work =?

F=force =500N

S=displacement =0m

please feel free to ask if you have any questions

5 0

4 years ago

The glass is attracting the pieces of paper. What does

choli [55]

Answer: The glass and the paper have different charges

Explanation:

7 0

4 years ago

Read 2 more answers

Calculate the volume of this regular solid.

Nataly [62]

Answer:

V = 42.41cm^3

Explanation:

In order to calculate the volume of the solid, you use the following formula:

$V=\frac{1}{3}\pi r^2 h$

where

r: radius of the circular base of the cone = 3 cm

h: height from the circular base to the peak of the cone = 4.5 cm

You replace the values of r and h in the formula for the volume V:

$V=\frac{1}{3}\pi(3cm)^2(4.5)=42.411cm^3\approx42.41cm^3$

hence, the volume of the solid is 42.41 cm^3

5 0

3 years ago

The magnitude of the tidal force between the International Space Station (ISS) and a nearby astronaut on a spacewalk is approxim

vovikov84 [41]

Answer:

F = 4.47 10⁻⁶ N

Explanation:

The expression they give for the strength of the tide is

F = 2 G m M a / r³

Where G has a value of 6.67 10⁻¹¹ N m² / kg² and M which is the mass of the Earth is worth 5.98 10²⁴ kg

They ask us to perform the calculation

F = 2 6.67 10⁻¹¹ 135 5.98 10²⁴ 13 / (6.79 10⁶)³

F = 4.47 10⁻⁶ N

This force is directed in the single line at the astronaut's mass centers and the space station

4 0

3 years ago

uniform disk with mass 40.0 kg and radius 0.200 m is pivoted at its center about a horizontal, frictionless axle that is station

Alex787 [66]

Answer:

The magnitude of the tangential velocity is $v= 0.868 m/s$

The magnitude of the resultant acceleration at that point is $a = 4.057 m/s^2$

Explanation:

From the question we are told that

The mass of the uniform disk is $m_d = 40.0kg$

The radius of the uniform disk is $R_d = 0.200m$

The force applied on the disk is $F_d = 30.0N$

Generally the angular speed i mathematically represented as

$w = \sqrt{2 \alpha \theta}$

Where $\theta$ is the angular displacement given from the question as

$\theta = 0.2000 rev = 0.2000 rev * \frac{2 \pi \ rad }{1 rev}$

$=1.257\ rad$

$\alpha$ is the angular acceleration which is mathematically represented as

$\alpha = \frac{torque }{moment \ of \ inertia} = \frac{F_d * R_d}{I}$

The moment of inertial is mathematically represented as

$I = \frac{1}{2} m_dR^2_d$

Substituting values

$I = 0.5 * 40 * 0.200^2$

$= 0.8kg \cdot m^2$

Considering the equation for angular acceleration

$\alpha = \frac{torque }{moment \ of \ inertia} = \frac{F_d * R_d}{I}$

Substituting values

$\alph$ $\alpha = \frac{(30.0)(0.200)}{0.8}$

$= 7.5 rad/s^2$

Considering the equation for angular velocity

$w = \sqrt{2 \alpha \theta}$

Substituting values

$w =\sqrt{2 * (7.5) * 1.257}$

$= 4.34 \ rad/s$

The tangential velocity of a given point on the rim is mathematically represented as

$v = R_d w$

Substituting values

$= (0.200)(4.34)$

$v= 0.868 m/s$

The radial acceleration at hat point is mathematically represented as

$\alpha_r = \frac{v^2}{R}$

$= \frac{0.868^2}{0.200^2}$

$= 3.7699 \ m/s^2$

The tangential acceleration at that point is mathematically represented as

$\alpha _t = R \alpha$

Substituting values

$\alpha _t = (0.200) (7.5)$

$= 1.5 m/s^2$

The magnitude of resultant acceleration at that point is

$a = \sqrt{\alpha_r ^2+ \alpha_t^2 }$

Substituting values

$a = \sqrt{(3.7699)^2 + (1.5)^2}$

$a = 4.057 m/s^2$

7 0

4 years ago