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MAVERICK [17]
3 years ago
10

Where does the circumference of each kind of triangle lie? Question 1 options: Inside the triangle. Outside the triangle. On the

hypotenuse. 1. Acute Triangle 2. Obtuse Triangle 3. Right Triangle

Mathematics
1 answer:
stiks02 [169]3 years ago
4 0

Answer:

Inside the triangle - Acute Triangle

Outside the triangle - Obtuse Triangle

On the hypotenuse - Right Triangle

Step-by-step explanation:

The <u>circumcenter</u> is the point where the perpendicular bisectors of a triangle intersect.

In the special case of a right triangle, the circumcenter lies exactly at the midpoint of the hypotenuse.

The circumcenter of an acute triangle lies inside the triangle.

The circumcenter of an obtuse triangle lies outside the triangle.

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The equation a=1/2(b^1+b^2)h can be determined the area, a, of a trapezoid with height, h, and base lengths, b^1 and b^2 Which a
Evgesh-ka [11]

The complete question is as follows.

The equation a = \frac{1}{2}(b_1 + b_2 )h can be used to determine the area , <em>a</em>, of a trapezoid with height , h, and base lengths, b_1 and b_2. Which are equivalent equations?

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(b) \frac{a}{2h} - b_2 = b_1

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(d) \frac{2a}{b_1 + b_2} = h

(e) \frac{a}{2(b_1 + b_2)} = h

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Step-by-step explanation: To determine b_1:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = b_1 + b_2

\frac{2a}{h} - b_2 = b_1

To determine h:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{(b_1 + b_2)} = h

To determine b_2

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = (b_1 + b_2)

\frac{2a}{h} - b_1 = b_2

Checking the alternatives, you have that \frac{2a}{h} - b_2 = b_1 and \frac{2a}{(b_1 + b_2)} = h, so alternatives <u>A</u> and <u>D</u> are correct.

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