Answer:
The will be increased by three times of the original volume
Explanation:
Answer:
new volume = 4.458 Liters
Explanation:
A balloon inflated in a room at 24°c has a volume of 4.00Liters The balloon is heated to a temperature of 58°c.What is the new volume if the pressure remains constant
charles law
volume1/temperature1 = volume2/temperature2
temperature has to be converted to kelvin
temperature 1 = 24+273=297
temperature 2 = 58+273=
4/297 = volume2/331
volume2 = (4*331)/297
volume2 = 4.45791245791 Liters
https://brainly.in/question/10937106?
The number of mole will be 65.81 mole.
An ideal gas would be one for which both the overall volume of the molecules and even the forces that exist between them are so negligible as to have no influence on the behavior of something like the gas.
Number of ideal gas can be calculated by using the formula:
PV = nRT
where, p is pressure, n is number of mole, R is gas constant and T is temperature.
Given data:
V= 1750 = 1750 L
P = 125,000 p = 1.2 atm
R = 0.082 L /mole kelvin
T = 273+127 = 400 K
Now, put the value of given data in above equation.
1.23atm x 1750L = n x 0.0820atm x Liter/ mole x kelvin x 400K
n = 65.81 mole.
Therefore, the number of mole will be 65.81 mole
To know more about mole
brainly.com/question/21050624
#SPJ4
The lowest smallest whole-number coefficient for H₂S is 5. Option C
<h3>What is the smallest whole-number coefficient for H₂S?</h3>
Now we know that a redox reaction is one in which there is a loss and gain of electrons One specie is oxidized (looses electrons) while another specie is reduced (gains electrons). The electrons must be transferred leading to an increase in oxidation number of one specie and a decrease in the oxidation number of another.
Now the reduction half equation is;
MnO4^-(aq) + 8H^+(aq) + 5e^- ----> Mn^2+(aq) + 4H2O (l)
The oxidation half equation is;
H2S(aq) ----> S^2-(aq) + 2H^+(aq) + 2e^-
Multiplying the reduction half equation by 2 and the oxidation half equation is 5
2MnO4^-(aq) + 16H^+(aq) + 10e^- ----> 2Mn^2+(aq) + 8H2O (l)
And;
5H2S(aq) ----> 5S^2-(aq) + 10H^+(aq) + 10e^-
The overall balanced reaction equation is;
2MnO4^-(aq) + 6H^+(aq) + 5H2S(aq) ----> 2Mn^2+(aq) + 8H2O (l) + 5S^2-(aq)
Thus the lowest smallest whole-number coefficient for H₂S is 5.
Learn more about redox reaction:brainly.com/question/13293425
#SPJ1