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3 years ago

State Modern periodic Table

Chemistry

1 answer:

Kaylis [27]3 years ago

5 0

Answer:

According to the modern periodic law, the properties of the elements and their compounds are a periodic function of their atomic numbers. Thus, in the modern periodic table, atomic number forms the basis of the classification of elements;The modern table is called 'long form' of the periodic table.

hope this helps

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The formula for binary ionic compound formed between cesium and fluorine

OleMash [197]

Answer:

Cesium fluoride(CsF)

Explanation:

A binary compound is a compound that is composed of 2 distinct element. An ionic compound is composed of ions, usually one is a metal why the other is a non metal. One element gives out electron to form cation and the other receives electron to form anion in a binary compound.

Cesium is a group 1 element and it has one valence electron and it can easily donate this 1 electron to form a bond with other element. Group 1 element are generally very reactive. Cesium is a metal

Fluorine is in group 7 of the periodic table and is a non metal .Fluorine have 7 valency electron and requires 1 electron to form a stable octet.

When cesium and fluorine bond to form a binary compound cesium donate 1 electron and fluorine receives the 1 electron for both element to form a stable octet. The formula for the binary ionic compound of cesium and fluorine can therefore be expressed as Cesium fluoride(CsF)

7 0

2 years ago

Even though lead is toxic, lead compounds were used in ancient times as white pigments in cosmetics. What is the percentage of l

Gekata [30.6K]

<u>Answer:</u> The mass percent of lead in lead (IV) carbonate is 63.32 %

<u>Explanation:</u>

The given chemical formula of lead (IV) carbonate is $Pb(CO_3)_2$

To calculate the mass percentage of lead in lead (IV) carbonate, we use the equation:

$\text{Mass percent of lead}=\frac{\text{Mass of lead}}{\text{Mass of lead (IV) carbonate}}\times 100$

Mass of lead = (1 × 207.2) = 207.2 g

Mass of lead (IV) carbonate = [(1 × 207.2) + (2 × 12) + (6 × 16)] = 327.2 g

Putting values in above equation, we get:

$\text{Mass percent of lead}=\frac{207.2g}{327.2g}\times 0100=63.32\%$

Hence, the mass percent of lead in lead (IV) carbonate is 63.32 %

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2 years ago

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2 years ago

When preparing a buret for use in lab, the buret must always be cleaned thoroughly. prior to being filled with solution, the bur

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2 years ago

an apple pie needs 10 large apples, 2 crusts (top and bottom), one tablespoon of cinnamon. write a balanced equation that fits t

nasty-shy [4]

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2 years ago

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State Modern periodic Table​

State Modern periodic Table