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Ulleksa [173]
3 years ago
15

What are 3 Properties of Convalent electrons

Chemistry
1 answer:
yKpoI14uk [10]3 years ago
4 0
Do not ionize in solutions
Poor conductors of electricity/heat
Low melting/boiling points
gases or liquids at room temperature
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I NEED HELP ASAP IF YOU GET IT CORRECT I WILL MARK YOU AS BRAINLIEST
masya89 [10]

Answer:

2 tall 2 short.

Explanation:

If 1 is tall, and 1 is short, 50% would be tall, and the other 50% would be short.

4 0
3 years ago
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What is the ph of a 3x10-8M H+ solution
Lelu [443]

Answer:

The pH of the solution is 7, 52

Explanation:

The pH gives us an idea of the acidity or alkalinity of a solution. Is calculated:

pH = -log (H +)

pH= -log ( 3x10-8)= <em>7, 52</em>

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2.568%20%5Ctimes%205.8%7D%7B4.186%7D%20" id="TexFormula1" title=" \frac{2.568 \ti
melomori [17]
Using a calculator:

(2.568 x 5.8)/4.186 = 3.5581460…
= 3.56 (3sf)

You didn’t specify the correct number of significant figures needed.
3 0
2 years ago
Any method of determining whether an event or object is older or younger than others
Inga [223]
The answer is relative dating, btw

6 0
3 years ago
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The equilibrium constant for the dissolution of silver chloride (AgCl(s) Ag+(aq) + Cl–(aq)) has a value of 1.79 × 10–10. Which s
ryzh [129]

"Silver chloride is essentially insoluble in water" this statement is true for the equilibrium constant for the dissolution of silver chloride.

Option: b

<u>Explanation</u>:

As silver chloride is essentially insoluble in water but also show sparing solubility, its reason is explained through Fajan's rule. Therefore when AgCl added in water, equilibrium take place between undissolved and dissolved ions. While solubility product constant \left(\boldsymbol{K}_{s p}\right) for silver chloride is determined by equilibrium concentrations of dissolved ions. But solubility may vary also at different temperatures.  Complete solubility is possible in ammonia solution as it form stable complex as water is not good ligand for Ag+.  

To calculate \left(\boldsymbol{K}_{s p}\right) firstly molarity of ions are needed to be found with formula: \text { Molarity of ions }=\frac{\text { number of moles of solute }}{\text { Volume of solution in litres }}

Then at equilibrium cations and anions concentration is considered same hence:

\left[\mathbf{A} \mathbf{g}^{+}\right]=[\mathbf{C} \mathbf{I}]=\text { molarity of ions }

Hence from above data \left(\boldsymbol{K}_{s p}\right) can be calculated by: \left(\boldsymbol{K}_{s p}\right) = \left[\mathbf{A} \mathbf{g}^{+}\right] \cdot[\mathbf{C} \mathbf{I}]

6 0
3 years ago
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