A binary compound is a compound that contain two different chemical elements in it. These compounds may be molecular or may also exist in other forms such as solid. In this case Barium and Beryllium are not binary compounds since they are independent elements, Calcium hydroxide is also not a binary compound since it has more than two chemical elements. Therefore,carbon dioxide is the binary compound since it contains two chemical elements ( carbon and oxygen)
Answer:
If you increase the concentration of a reactant, there will be more of the chemical present. More reactant particles moving together allow more collisions to happen and so the reaction rate is increased. The higher the concentration of reactants, the faster the rate of a reaction will be.
Answer:
WATER
Explanation:
The another name for dihydrogen monoxide is water
PH to maximize the dissociation of acetic acid so as to push back the amount of acetate dissociating from the mystery compound.
<span>
Ksp = [X+][C2H3O2-] = 9.5*10^-6 </span>
<span>Substituting in the desired value for [X+] </span>
<span>9.5*10^-6 = (5.0*10^-3)x </span>
x, or acetate concentration, is .0019
<span>Now, we calculate the Ka of acetic acid: </span>
<span>pKa = -logKa </span>
<span>4.76 = -logKa </span>
<span>Ka = 1.738*10^-5 </span>
<span>We want the concentration of acetate to be .0019, so we plug that into our acid dissociation constant expression: </span>
<span>Ka = [H+][C2H3O2-]/[HC2H3O2] </span>
1.738*10^-5<span> = [H+](.0019)/1</span>
<span>[H+] = .00915</span>
<span>pH = -log[H+] </span>
<span>pH = -log(.00915) </span>
pH = 2.04
Answer : The specific heat of this substance is, 1.13 J/g.K
Explanation :
Molar heat capacity : It is defined as the amount of heat absorbed by one mole of a substance to raise its temperature by one degree Celsius.
As we are given that the chemical formula of compound is, 
First we have to calculate the molar mass of given compound.
Molar mass of = 
Molar mass of = 78 g/mol
Now we have to calculate the specific heat of this substance.
Specific heat of this substance = 
Specific heat of this substance = 
Specific heat of this substance = 1.13 J/g.K
Thus, the specific heat of this substance is, 1.13 J/g.K
