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Dimas [21]
3 years ago
10

"Close the door! We aren't heating the outdoors!" is a phrase my father used, especially in the winter. As a matter of fact, all

energy consumption eventually turns into heat, which becomes part of Earth's heat. Wikipedia gives the total energy consumption in 2008 to be 15 TW (15 terawatts = 15 x 1012 W). We can spread this power out over the entire surface area of the Earth to calculate the radiative forcing equivalent of the direct use of energy to be _____ W/m2. The radiating area of the Earth is 4Ï R2, where the radius of the Earth is about 6366 km. (watch your unit conversions).
Physics
1 answer:
Alina [70]3 years ago
7 0

Answer:

I = 2,945 10⁻² W / m²

Explanation:

In this exercise it is requested to calculate the intensity of radiation that is defined by the power per unit of ares

           I = P / A

Approach the Earth as a sphere, with area

         A = 4π R²

Let's replace

           I = P / 4π R²

Let's reduce the magnitudes

      W = 15 10¹² W

       R = 6366 km (10³ m / 1km) = 6.366 10⁶ m

Let's calculate

       I = 15 10¹²/4π (6.366 10⁶)²2

       I = 2,945 10⁻² W / m²

This is a very small amount compared to the intensity coming from the Sun 1353 W / m²

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. Energy can neither be created nor be destroyed, but it can be changed from one form to another", this law is known as kinetic
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Answer:

The law of conservation of energy

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3 years ago
I NEED HELP PLEASE, THANKS! :)
Zina [86]

Answer:

charge C = greatest net force

charge B = the smallest net force

ratio  = 9 : 1

Explanation:

we know that in Electrostatic Forces, when 2 charges are at same sign then they repel each other and if they are different signed charges then they attract each other

so as per Coulomb's formula of Electrostatic Forces

F = \frac{k\ q_1\ q_2}{r^2}     .....................1

and here k is 9 × 10^9 N.m²/c² and we consider each charge at distance d

so two charge force at A to B is

F1 = \frac{k\ q^2}{d^2}

and force between charges at A to C, at 2d distance

F1 = \frac{k\ q^2}{(2d)^2}  =  \frac{k\ q^2}{4d^2}

force between charges at A to D,  3d distance

F1 = \frac{k\ q^2}{(3d)^2}  = \frac{k\ q^2}{9d^2}  

so

Charge a It receives force to the left from b and c and to the right from d

so at a will be

F(a)  = -F1 - F2 + F3             ....................2

put here value

F(a) = -\frac{k\ Q^2}{d^2}-\frac{k\ Q^2}{4d^2}+\frac{k\ Q^2}{9d^2}

solve it

F(a) = \frac{k\ q^2}{d^2}(-1-\frac{1}{4}+\frac{1}{9})  

F(a) = -\frac{41}{36}\ F1   = 1.13 F1  

and

Charge b It  receives force to the right from a and d and to the left from c

F(b) = F1 - F1 + F2            ....................3

F(b)  =  \frac{k\ q^2}{d^2}-\frac{k\ q^2}{d^2}+\frac{k\ q^2}{4d^2}    

F(b)  = \frac{1}{4} \ F1    =  0.25 F1

and

Charge c It receives forces to the right from all charges.

F(c) = F2 + F 1 + F 1      ....................4

F(c) = \frac{k\ q^2}{4d^2}+\frac{k\ q^2}{d^2}+\frac{k\ q^2}{d^2}      

F(c) =  \frac{9}{4} \ F1   = 2.25 F1

and

Charge d It receives forces to the left from all charges

F(d) = - F3 - F2 -F 1      ....................5

F(d) = -\frac{k\ q^2}{9d^2}-\frac{k\ q^2}{4d^2}-\frac{k\ q^2}{d^2}  

so

F(d) = -\frac{49}{36} \ F1    = 1.36 F1

and

now we get here ratio of the greatest to the smallest net force that is

ratio = \frac{2.25}{0.25}

 ratio  = 9 : 1

5 0
3 years ago
Elements with positive valences usually ______ electrons
Leno4ka [110]
The answer is donate, therefore elements with positive valences usually donate electrons
7 0
3 years ago
What is the purpose of the report​
AfilCa [17]

Answer:

The purpose of report : Reports communicate information which has been compiled as a result of research and analysis of data and of issues .

5 0
3 years ago
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4. Heat is added to an ideal gas and the gas expands. In such a process the temperature
Bumek [7]

Answer:

is high as 100 degrees c

Explanation:

due to high heat gas expands fast than normal

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3 years ago
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