Answer:

Explanation:
Given data
mass of copper m=4.85 kg
charge of electron qe= -1.6×10⁻¹⁹C
To find
Number of electron n must be removed
Solution
Equate the magnitude of electric force Fe of repulsion between two two spheres to the magnitude of gravitational force of attraction between them
So

where q is charge of each sphere which is equal to number n of removed electrons multiplied by each charge qe
So

100/2.5 is 40.
40 is the energy that is being produced
Answer:
The force parallel to the horizontal is 26.24 N
Explanation:
She pulls on the leash with a force F = 30 N, this force, since its at an angle of 29° (i will cal this angle
), it has a force component on x (the horizontal, i will call this force
) and a force component on y (the vertical, i will call this
).
This can be seen in the attached picture.
Since we are asked about the force parallel to the horizontal, we need to find the component of the force
, since
is the adjacent angle, we need to use cosine:

since
and 



The force parallel to the horizontal is 26.24 N
Answer:
4.5 N upward
Explanation:
You take the net force and subtract it from the weight
~DjMia~