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3 years ago

When You lift a load, the resistance force is ? A. magnetism b. gravity

Physics

2 answers:

IceJOKER [234]3 years ago

8 0

The answer to the question is gravity
B

serious [3.7K]3 years ago

5 0

Answer:

B gravity

Explanation:

when you lift a load you feel that the load is heavy the load becomes heavy due to gravitational force that pulls the load towards it

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What is a formula unit

Nana76 [90]

A formula unit is the empirical formula for an ionic compound. It is the lowest possible ratio of the cations and anions of a given ionic compound.

3 0

2 years ago

A ball rolls off a table with a horizontal velocity of 3 m/s. If it takes 0.3 seconds for the ball to reach the floor, how high

LekaFEV [45]

The height of the table above the ground is 0.45 m.

<h3>Data obtained from the question</h3>

From the question given above, the following data were obtained:

Horizontal velocity (u) = 3 m/s
Time (t) = 0.3 s
Acceleration due to gravity (g) = 10 m/s²
Height (h) =?

<h3>How to determine the height </h3>

The height of the table can be obtained by using the following formula:

h = ½gt²

h = ½ × 10 × 0.3²

h = 5 × 0.09

h = 0.45 m

Thus, the height of the table is 0.45 m

Learn more about motion under gravity:

brainly.com/question/26275209

6 0

2 years ago

a ball is projected upward at time t = 0.00 s from a point on a roof 70 m above the ground. The ball rises, then falls and strik

grin007 [14]

Answer: 17.68 s

Explanation:

This problem is a good example of Vertical motion, where the main equation for this situation is:

$y=y_{o}+V_{o}t-\frac{1}{2}gt^{2}$ (1)

Where:

$y=0$ is the height of the ball when it hits the ground

$y_{o}=70 m$ is the initial height of the ball

$V_{o}=82m/s$ is the initial velocity of the ball

$t$ is the time when the ball strikes the ground

$g=9.8m/s^{2}$ is the acceleration due to gravity

Having this clear, let's find $t$ from (1):

$0=70m+(82m/s)t-\frac{1}{2}(9.8m/s^{2})t^{2}$ (2)

Rewritting (2):

$-\frac{1}{2}(9.8m/s^{2})t^{2}+(82m/s)t+70m=0$ (3)

This is a quadratic equation (also called equation of the second degree) of the form $at^{2}+bt+c=0$ , which can be solved with the following formula:

$t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$ (4)

Where:

$a=-\frac{1}{2}(9.8m/s^{2}$

$b=82m/s$

$c=70m$

Substituting the known values:

$t=\frac{-82 \pm \sqrt{82^{2}-4(-\frac{1}{2}(9.8)(70)}}{2a}$ (5)

Solving (5) we find the positive result is:

$t=17.68 s$

7 0

3 years ago

A 16 foot ladder is leaning against a wall. If the top of the ladder slides down the wall at a rate of 3 feet per second, how fa

JulsSmile [24]

Answer:

11.625

Explanation:

L = length of the ladder = 16 ft

$v_{y}$ = rate at which top of ladder slides down = - 3 ft/s

$v_{x}$ = rate at which bottom of ladder slides

y = distance of the top of ladder from the ground

x = distance of bottom of ladder from wall = 4 ft

Using Pythagorean theorem

L² = x² + y²

16² = 4² + y²

y = 15.5 ft

Also using Pythagorean theorem

L² = x² + y²

Taking derivative both side relative to "t"

$0 = 2x\frac{\mathrm{d} x}{\mathrm{d} t} + 2y\frac{\mathrm{d} y}{\mathrm{d} t}$

$0 = x v_{x} + y v_{y}$

$0 = 4 v_{x} + (15.5) (- 3)$

$v_{x}$ = 11.625 ft/s

7 0

3 years ago

Trình bày về Thí nghiệm tán xạ Rutherford, phát hiện proton.

Setler [38]

Answer:

Any other language I don't know this language

6 0

3 years ago