The emf induced in the second coil is given by:
V = -M(di/dt)
V = emf, M = mutual indutance, di/dt = change of current in the first coil over time
The current in the first coil is given by:
i = i₀
i₀ = 5.0A, a = 2.0×10³s⁻¹
i = 5.0e^(-2.0×10³t)
Calculate di/dt by differentiating i with respect to t.
di/dt = -1.0×10⁴e^(-2.0×10³t)
Calculate a general formula for V. Givens:
M = 32×10⁻³H, di/dt = -1.0×10⁴e^(-2.0×10³t)
Plug in and solve for V:
V = -32×10⁻³(-1.0×10⁴e^(-2.0×10³t))
V = 320e^(-2.0×10³t)
We want to find the induced emf right after the current starts to decay. Plug in t = 0s:
V = 320e^(-2.0×10³(0))
V = 320e^0
V = 320 volts
We want to find the induced emf at t = 1.0×10⁻³s:
V = 320e^(-2.0×10³(1.0×10⁻³))
V = 43 volts
Magnetic field strength decreases as you get farther from the poles of the magnet.
<h3>Explanation</h3>
There are three ways to change the magnetic flux across a loop: Change the strength of the magnetic field across the surface (raise, reduce).
It doesn’t matter whether you move the coil while keeping the magnet fixed or the other way around if you want to change the surface area of the loop (raise by expanding the loop, decrease by reducing the loop).
The way they move in respect to one another determines how the magnetic flux across the coil changes. The direction in which the galvanometer needle deflects depends on which side of the coil confronts the magnet when you move it. The coil ends are labelled to show which goes to the red wire and which goes to the black wire.
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Answer:
I believe the answer is that the light with the higher frequency refracts more than light with a lower frequency
Explanation:
Answer:
The intensity level of sound 2 is 93.3\ W/m².
Explanation:
Given that,
Intensity of sound 1 = 45.0 W/m²
Intensity level of sound 2 = 3.2 dB

We need to calculate the intensity
Using equation of the sound level intensity



The intensity of sound 2 is greater than 3.2 dB.
Therefore,


Calculate the intensity of sound 2



Hence, The intensity level of sound 2 is 93.3\ W/m².