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Greeley [361]
3 years ago
6

Two teams are playing tug of war. The team on the right side is pulling with a force of 4332 N. The team on the left is pulling

with a force of 4251 N. What direction will the rope move and why?
18PTS

Physics
2 answers:
OleMash [197]3 years ago
6 0
As the greater force of tension (by 81N) is exerted by the team on the right the rope will move to the right.
Iteru [2.4K]3 years ago
5 0

The rope will pull to the right side. This will happen because the force of the right team is higher (4332 N) than the team on the left (4251 N). And if they need it the extra force would be 81 to the right.

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a 2100-kg car drives with a speed of 18 m/s onb a flat road around a curve that has a radius of curvature of 83m. The coefficien
Law Incorporation [45]

Answer:

<u>The magnitude of the friction force is 8197.60 N</u>

Explanation:

Using the definition of the centripetal force we have:

\Sigma F=ma_{c}=m\frac{v^{2}}{R}

Where:

  • m is the mass of the car
  • v is the speed
  • R is the radius of the curvature

Now, the force acting in the motion is just the friction force, so we have:

F_{f}=m\frac{v^{2}}{R}

F_{f}=2100\frac{18^{2}}{83}

F_{f}=8197.60 \: N

<u>Therefore the magnitude of the friction force is 8197.60 N</u>

I hope it helps you!

7 0
3 years ago
You set your stationary bike on a high 80-N friction-like resistive force and cycle for 30 min at a speed of 8.0 m/s . Your body
stellarik [79]

A) The change in internal chemical energy is 1.15\cdot 10^7 J

B) The time needed is 1 minute

Explanation:

First of all, we start by calculating the power output of you and the bike, given by:

P=Fv

where

F = 80 N is the force that must be applied in order to overcome friction and travel at constant speed

v = 8.0 m/s is the velocity

Substituting,

P=(80)(8.0)=640 W

The energy output is related to the power by the equation

P=\frac{E}{t}

where:

P = 640 W is the power output

E is the energy output

t = 30 min \cdot 60 = 1800 s is the time elapsed

Solving for E,

E=Pt=(640)(1800)=1.15\cdot 10^6 J

Since the body is 10% efficient at converting chemical energy into mechanical work (which is the output energy), this means that the change in internal chemical energy is given by

\Delta E = \frac{E}{0.10}=\frac{1.15\cdot 10^6}{0.10}=1.15\cdot 10^7 J

B)

From the previous part, we found that in a time of

t = 30 min

the amount of internal chemical energy converted is

E=1.15\cdot 10^7 J

Here we want to find the time t' needed to convert an amount of chemical energy of

E'=3.8\cdot 10^5 J

So we can setup the following proportion:

\frac{t}{E}=\frac{t'}{E'}

And solving for t',

t'=\frac{E't}{E}=\frac{(3.8\cdot 10^5)(30)}{1.15\cdot 10^7}=1 min

Learn more about power and energy:

brainly.com/question/7956557

#LearnwithBrainly

3 0
3 years ago
Reflected waves change their wavelength by ______ when reflected.
natita [175]

Answer:

i think its c

Explanation:

trust me

4 0
2 years ago
A force of 210 N is applied to an object and the object accelerates at 14m/s2. Determine the mass of the object in kg.
lisabon 2012 [21]

Answer:

15 kg

Explanation:

F = m*a

F/a = m

210/14 = 15 kg

7 0
3 years ago
A hockey puck of mass m1=165 g slides from left to right with an initial velocity of 15.5 m/s. It collides head on with a second
Fynjy0 [20]

Answer:

it may be -6 m/s

Explanation:

3 0
3 years ago
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