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3 years ago

1. applied research

Physics

1 answer:

ladessa [460]3 years ago

7 0

Answer:

Applied Research: It is a research conducted to find solutions for specific problems in a particular field of studies. Example, health effects on food that are genetically modified.

Basic research: It is basic research on any field to have a clear understanding of something from the existing knowledge. Example, the study on evolution of the living organisms.

Control: To increase the reliability of the result the scientific experiments decrease the number of variables (depending factors) in the experiment.

Dependent variable: This is a variable that determines the outcome of the result of an experiment depending on the independent variables. For example, stress influence the heart rate. Heart rate is a dependent variable.

Empirical evidence: It is the collection of scientific facts directly or indirectly. These facts support the scientific nature of the research. For example, measuring temperature, water freezing at a particular temperature and pressure.

Hypothesis: It is an explanation or assumption of a phenomenon based on limited empirical evidence. This is the first step of the research.

Independent variable: This is a variable that the experimenter has control to change. For example, stress influence the heart rate. Stress is an independent variable.

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Which surface feature of the moon is characterized by mountainous areas?

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Crates is the correct answer because they create dents that make the bumps of mountains.

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3 years ago

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To initiate a nuclear reaction, an experimental nuclear physicist wants to shoot a proton into a 5.50-fm-diameter 12C nucleus. T

Crazy boy [7]

Answer:

The value is $u = 3.23 *10^{7} \ m/s$

Explanation:

From the question we are told that

The diameter of the nucleus is $d = 5.50 \ fm = 5.50 *10^{-15} \ c$

The charge of the proton that makes up the nucleus is $Q_2 = \frac{12}{2} * 1.60 *10^{-19} =9.6*10^{-19} \ C$

The energy to be impacted is $KE_f = 2.30 \ MeV = 2.30 *10^{6} \ eV = 2.30 *10^{6} * 1.60 *10^{-19} = 3.68*10^{-13} \ J$

Generally the radius of the nucleus is mathematically represented as

$r = \frac{d}{2}$

=> $r = \frac{5.50 *10^{-15}}{2}$

=> $r = 2.75 *10^{-15} \ m$

Generally from the law energy conservation we have that

$Initial \ total \ energy \ of the \ proton = final \ total \ energy \ of the \ proton$

i.e

$T_i = T_f$

Here

$T_i = KE_i + PE_i$

Here $KE_i$ is the initial kinetic energy which is mathematically represented as

$KE_I = \frac{1}{2} * m * u ^2$

Here $PE_i$ is the initial potential energy of the proton and the value is 0 J given that the proton is moving

Also $T_f$ is mathematically represented as

$T_f = KE_f + PE_f$

Here

$PE_f$ is the final potential energy which is mathematically represented as

$PE_f = \frac{k * Q_1 * Q_2}{r}$

Here $Q_1$ is the charge on the proton with a value of $Q_1 = 1.60 *10^{-19} \ C$

$PE_f = \frac{9*10^{9} *(1.60 *10^{-19} ) * ( 9.6 *10^{-19})}{ 2.75 *10^{-15}}$

=> $PE_f = 5.027 *10^{-13 } \ J$

$KE_i + PE_i = KE_f + PE_f$

=> $\frac{1}{2} * m * u ^2 +0 = 3.68*10^{-13} + 5.027 *10^{-13 }$

Here m is the mass of the moving proton with value $m = 1.67*10^{-27} \ kg$

$\frac{1}{2} * 1.67*10^{-27} * u ^2 +0 = 3.68*10^{-13} + 5.027 *10^{-13 }$

=> $u = \sqrt{\frac{3.68*10^{-13} + 5.027 *10^{-13 }}{0.5 * 1.67*10^{-27}} }$

=> $u = 3.23 *10^{7} \ m/s$

5 0

3 years ago

What is used to determine the number of a type of atom in a compound based on the chemical name?

____ [38]

Are there options? because there is 2 things im thinking of

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3 years ago

The resistance and the magnitude of the current depend on the path that the current takes. The drawing shows three situations in

maria [59]

Answer: (a). Resistance = 0.4286ohms and Current (I) = 7A

(b). Resistance (R) = 0.027 ohms and Current (I) = 111.1A

(c). Resistance (R) = 0.1071 ohms and Current (I) = 28A

Explanation:

From the question, given that;

ρ = 1.5*10-2ῼ.m

Lo = 7cm = 0.07m

V = 3V

From the formula R = ρL/A, where A is the area of cross section, L is the length of material and ρ is the resistivity.

(A)

L = 4Lo and A = 2Lo*Lo

R = ρL/A

R = ρ4Lo/(2Lo*Lo)

R = 2ρ /Lo = 2*1.5*10-2/0.07

R = 0.4286 ῼ

From this the current becomes;

I = V/R = 3/ 0.4286 = 6.99 = 7A

(B)

L = Lo and A = 4Lo * 2Lo

R = ρL/A

R = ρLo/ (4Lo*2Lo) after eliminating Lo from both sides we get,

R = ρ/8Lo = 1.5*10-2 / 8*0.07

R = 0.027

Current (I) = V/R = 3/0.027 = 111.1A

(C)

L = 2Lo and A = Lo * 4Lo

R = ρL/A

R = ρ2Lo/ (Lo*4Lo) eliminating Lo from both sides we get,

R = ρ/2Lo = 1.5*10-2 / 2*0.07 = 0.1071

The current becomes;

I = V/R = 3/0.1071 = 28A

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4 years ago

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The calculation of momentum involves what?

Oxana [17]

If you're asking for the equation of momentum, it's p = mv.

"p" is the momentum
"m" is the mass
"v" is the velocity

I hope this helps a lot! (:

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4 years ago

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