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creativ13 [48]
3 years ago
11

Can you help me on both and I will give someone Brainiest

Mathematics
1 answer:
Brums [2.3K]3 years ago
8 0

Answer:

question 1 is 300

and question 2 is 24

Step-by-step explanation:

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How would you do 5^-1 (mod 26) ?
Yuri [45]

What we’re looking for is the value of k that will satisfy the equation.

The solution would be like this for this specific problem:

5k =1 (mod 26)

Check how 5*5 = 25 = -1 (mod 26)

In this way, 5*(-5) = -5*5 = -25 = -(-1) = 1 (mod 26)

Thus, k = -5 = 21 (mod 26)

And 5^-1 = 21 (mod 26)

I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

3 0
3 years ago
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andriy [413]
B.

x/400 = 24/100
24 × 400 / 100 = x
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4 years ago
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Lesechka [4]

x greater than negative 2, because ln(x) is undefined for x <= 0 (-2+2=0, -1.999...+2>0)

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4 years ago
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Factor completely 3x2 + x + 7.
OlgaM077 [116]
It should be prime :DDD
6 0
4 years ago
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In a parallel circuit, ET = 240 V, R = 47 kΩ, and XL = 50 kΩ. What is the reactive power?
Fittoniya [83]

Answer:

Reactive power is 1.152 VARs

Step-by-step explanation:

We are given that in a parallel circuit,E_{T}=240V,R=47kΩ and X_{L}=50kΩ.

reactive power means the dissipating power resulting from inductive and capacitive loads measured in volt-amperes reactive(VAR).Since our circuit has inductor only, reactive power will be power dissipated from inductor.

Current through inductor=\frac{E_{T}}{X_{L}} =\frac{240}{50}=4.8milli amps=0.0048 A

Reactive power = (current flowing through inductor)X (Voltage across inductor)

Hence reactive power = 0.0048 X 240=1.152 VARs

7 0
3 years ago
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