What we’re looking for is the
value of k that will satisfy the equation.
The solution would be like this
for this specific problem:
5k =1 (mod
26)
Check how 5*5
= 25 = -1 (mod 26)
In this way,
5*(-5) = -5*5 = -25 = -(-1) = 1 (mod 26)
Thus, k = -5
= 21 (mod 26)
And 5^-1 =
21 (mod 26)
I am hoping that this answer has
satisfied your query and it will be able to help you in your endeavor, and if
you would like, feel free to ask another question.
x greater than negative 2, because ln(x) is undefined for x <= 0 (-2+2=0, -1.999...+2>0)
Answer:
Reactive power is 1.152 VARs
Step-by-step explanation:
We are given that in a parallel circuit,
,R=47kΩ and
=50kΩ.
reactive power means the dissipating power resulting from inductive and capacitive loads measured in volt-amperes reactive(VAR).Since our circuit has inductor only, reactive power will be power dissipated from inductor.
Current through inductor=
milli amps=0.0048 A
Reactive power = (current flowing through inductor)X (Voltage across inductor)
Hence reactive power = 0.0048 X 240=1.152 VARs