All three choices are correct.
Explanation:
The given data is as follows.
C = 
R = 
ohm
C
Q = 
Formula to calculate the time is as follows.
![Q_{t} = Q_{o} [e^{\frac{-t}{\tau}]](https://tex.z-dn.net/?f=Q_%7Bt%7D%20%20%3D%20Q_%7Bo%7D%20%5Be%5E%7B%5Cfrac%7B-t%7D%7B%5Ctau%7D%5D)
![13.5 \times 10^{-6} = 100 \times 10^{-6} [e^{\frac{-t}{2}}]](https://tex.z-dn.net/?f=13.5%20%5Ctimes%2010%5E%7B-6%7D%20%3D%20100%20%5Ctimes%2010%5E%7B-6%7D%20%5Be%5E%7B%5Cfrac%7B-t%7D%7B2%7D%7D%5D)
0.135 = 
= 7.407
t = 4.00 s
Therefore, we can conclude that time after the resistor is connected will the capacitor is 4.0 sec.
This is kinda confusing. I wish u just to a screenshot of the problem but here goes...
Forest at highest latitudes- Hardwood trees/deer, squirrel, foxes
Praries/temperate climate- Mostly small mammals/scrubs/steppes
High humidity/rainfall near equator- Abundant thick vegatation/manny species
No trees/ polar bears/ mosses- 25cm rain/few animals
Answer:
F = 156.3 N
Explanation:
Let's start with the top block, apply Newton's second law
F - fr = 0
F = fr
fr = 52.1 N
Now we can work with the bottom block
In this case we have two friction forces, one between the two blocks and the other between the block and the surface. In the exercise, indicate that the two friction coefficients are equal
we apply Newton's second law
Y axis
N - W₁ -W₂ = 0
N = W₁ + W₂
as the two blocks are identical
N = 2W
X axis
F - fr₁ - fr₂ = 0
F = fr₁ + fr₂
indicates that the lower block is moving below block 1, therefore the upper friction force is
fr₁ = 52.1 N
fr₁ = μ N
a
s the normal in the lower block of twice the friction force is
fr₂ = μ 2N
fr₂ = 2 μ N
fr₂ = 2 fr₁
we substitute
F = fr₁ + 2 fr₁
F = 3 fr₁
F = 3 52.1
F = 156.3 N
You can't. Velocity and acceleration measure two different things, so their units are incompatible. It's like asking, "How many meters does this book weigh?"
Maybe you mean "find" acceleration using given velocities, or a velocity function?
