Answer:
(a) The x-component of velocity is 31.55 km/h
(b) The y-component of velocity is 44.92 km/hr
Solution:
As per the solution:
The relative position of ship A relative to ship B is 4.2 km north and 2.7 km east.
Velocity of ship A, 
= 22 km/h towards South = 
Velocity of ship B, 
= 39 km/h Towards North east at an angle of 
= 
Now, the velocity of ship A relative to ship B:
Now,
Answer:
here you go 4 m/s^2......tadaa
Given: v0= 18.0 m/s, y0=0m, yf=11m, g=-9.81 m/s^2
v0= initial velocity, vf= final velocity, y0= initial height, yf= final height, g= gravity, sqrt()= square root, ^2=squared
vf^2=v0^2 + (2)(g)(yf-y0)
vf^2=(18.0 m/s)^2+(2)(-9.81 m/s^2)(11 m-0m)
vf^2=18.0 m/s)^2 + (-19.62 m/s^2)(11 m)
vf^2=(324 m^2/s^2) - (215.82 m^2/s^2)
vf^2=108.18 m^2/s^2
vf=sqrt(108.18 m^2/s^2)
vf=10.4 m/s
Answer:
AS- X 3.42 Y 3. B) X Y c) x Ross TET V V. a 1.71 1.71 LLL LLL 2.42 N al
Explanation:
Answer:
Explanation: B. A change in particle position
