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aalyn [17]
3 years ago
7

12. One object has half the mass of another object. The first object also has half the ---.

Physics
1 answer:
Tanya [424]3 years ago
3 0

The first object also has half the inertia.

Answer: Option A

<u>Explanation:</u>

Inertia is the tendency of an object to remain in its state. It resists the change in the state of object due to any external forces. So the inertia is the property of an object to resists the change in its state due to any kind of external force. Thus as the mass decreases, the central mass of inertia of the object will also decrease as both are directly proportional to each other.

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Given Data: Diameter 'd' = 30 cm = 0.3 m Lifting Weight 'W' = mg = 2000*9.81 N = 19,620 N Calculations: Area of the lift 'A' = <span>pi\over4*d^2=pi\over4*0.3^2=0.07 m^2

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3 years ago
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Yosef is playing with different kinds of rubber bands. Some are very narrow and some are quite wide. Yosef is curious about the
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Answer:

He could have many different hypothesis, but here is one.

Explanation:

If rubber bands are wider, then the rubber bands will stretch further, because the wider a rubber band is the stronger it is.

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3 years ago
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The small spherical planet called "Glob" has a mass of 7.88×10^18 kg and a radius of 6.32×10^4 m. An astronaut on the surface of
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Answer: The small spherical planet called "Glob" has a mass of 7.88×1018 kg and a radius of 6.32×104 m. An astronaut on the surface of Glob throws a rock straight up. The rock reaches a maximum height of 1.44×103 m, above the surface of the planet, before it falls back down.

1) the initial speed of the rock as it left the astronaut's hand is 19.46 m/s.

2) A 36.0 kg satellite is in a circular orbit with a radius of 1.45×105 m around the planet Glob. Then the speed of the satellite is 3.624km/s.

Explanation: To find the answer, we need to know about the different equations of planetary motion.

<h3>How to find the initial speed of the rock as it left the astronaut's hand?</h3>
  • We have the expression for the initial velocity as,

                           v=\sqrt{2gh}

  • Thus, to find v, we have to find the acceleration due to gravity of glob. For this, we have,

                       g_g=\frac{GM}{r^2} =\frac{6.67*10^{-11}*7.88*10^{18}}{(6.32*10^4)^2}= 0.132

  • Now, the velocity will become,

                        v=\sqrt{2*0.132*1.44*10^3} =19.46 m/s

<h3>How to find the speed of the satellite?</h3>
  • As we know that, by equating both centripetal force and the gravitational force, we get the equation of speed of a satellite as,

                       v=\sqrt{\frac{GM}{r} } =\sqrt{\frac{6.67*10^{-11}*7.88*10^{18}}{1.45*10^5} } =3.624km/s

Thus, we can conclude that,

1) the initial speed of the rock as it left the astronaut's hand is 19.46 m/s.

2) A 36.0 kg satellite is in a circular orbit with a radius of 1.45×105 m around the planet Glob. Then the speed of the satellite is 3.624km/s.

Learn more about the equations of planetary motion here:

brainly.com/question/28108487

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2 years ago
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All of these are very important parts of studying physics EXCEPT
Sergeeva-Olga [200]

Answer:

4. deducing and applying natural laws

5 0
3 years ago
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At a objects highest point is the acceleration zero too?
puteri [66]

Answer:

Acceleration from gravity is always constant and downward, but the direction and magnitude of velocity change. At the highest point in its trajectory, the ball has zero velocity, and the magnitude of velocity increases again as the ball falls back toward the earth

Explanation:

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4 years ago
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