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IrinaK [193]
3 years ago
13

A cell has the reaction Co2+ (aq) + Cd(s) -------> Cd2+ (aq) + Co(s) E0cell = +0.120 V What is Ecell when [Co2+] = 0.00100 M

and [Cd2+] = 0.100 M (use 2 significant figures, dont write units)
Chemistry
1 answer:
musickatia [10]3 years ago
5 0

Answer:

USe this Nernst equation and find your required answer

Explanation:

E = E0 -  [0.0592 /n ] log [Cd+2]/[Co2+]

Wher Eo is  +0.120 V

[Cd+2] =0.1

[Co2+] = 0.001

n is number of electons transfered int he process and in your case it is = 2

E= 0.120- 0.0296 * log 100

  = ........  V

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3 years ago
Calculate the volume of 1M NaOH required to neutralize 200 cc of 2M HCI. What mass of sodium
Nezavi [6.7K]

NaOH+HCl-> NaCl+H2O

1 mole of NaOH

1 mole of HCl.

To calculate volume of NaOH

CaVa/CbVb= Na/Nb

Where Ca=2M

Cb=1M

Va=200cm³

Vb=xcm³

Substitute into the equation.

2×200/1×Vb=1/1

400/Vb=1/1

Cross multiply

Vb×1=400×1

Vb=400cm³

To calculate the mass of sodium chloride, NaCl from the neutralization rxn.

Mole of NaCl=1

Molar mass of NaCl= 23+35.5=58.5

Mass=xgrammes.

Mass of NaCl=Number of moles × Molar mass.

Substitute

Mass of NaCl= 1×58.5

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5 0
3 years ago
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how many grams of oxygen gas are needed to produce 10.0 grams of carbon dioxide according to the balanced equation of CH4
Alinara [238K]
Molar mass of :

O2 = 16 * 2 = 32 g/mol

CO2 = 12 + 16 * 2 = 44 g/mol

<span>Balanced chemical equation :
</span>
1 CH4 + 2 O2 = 1 CO2 + 2 H2O
               ↓              ↓
             2 moles     1 mole

2* 32 g O2 ----------> 1* 44 g CO2
     x g O2 ------------> 10.0 g CO2

44 x = 2 * 32*10.0

44 x = 640

x =  \frac{640}{44}

x = 14.54 g of O2





7 0
3 years ago
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