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IrinaK [193]
3 years ago
13

A cell has the reaction Co2+ (aq) + Cd(s) -------> Cd2+ (aq) + Co(s) E0cell = +0.120 V What is Ecell when [Co2+] = 0.00100 M

and [Cd2+] = 0.100 M (use 2 significant figures, dont write units)
Chemistry
1 answer:
musickatia [10]3 years ago
5 0

Answer:

USe this Nernst equation and find your required answer

Explanation:

E = E0 -  [0.0592 /n ] log [Cd+2]/[Co2+]

Wher Eo is  +0.120 V

[Cd+2] =0.1

[Co2+] = 0.001

n is number of electons transfered int he process and in your case it is = 2

E= 0.120- 0.0296 * log 100

  = ........  V

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Reaction Rates
inn [45]

Answer:

PART A 1st order in A and 0th order in B

Part B The reaction rate increases

Explanation:

<u>PART A </u>

The rate law of the arbitrary chemical reaction is given by

-r_A=k\times\left[A\right]^\alpha\times\left[B\right]^\beta\bigm

Replacing for the data

Expression 1 0.00639=k\times{0.12}^\alpha\times{0.22}^\beta

Expression 2 0.01280=k\times{0.24}^\alpha\times{0.22}^\beta

Expression 3 0.00639=k\times{0.12}^\alpha\times{0.11}^\beta

Making the quotient between the fist two expressions

\frac{0.00639}{0.01280}=\left(\frac{0.12}{0.24}\right)^\alpha

Then the expression for \alpha

\alpha=\frac{ln\frac{0.00639}{0.01280}}{ln\frac{0.12}{0.24}}=1\bigm

Doing the same between the expressions 1 and 3  

\frac{0.00639}{0.00639}=\left(\frac{0.22}{0.11}\right)^\beta

Then

\beta=\frac{ln\frac{0.00639}{0.00639}}{ln\frac{0.22}{0.11}}=0\bigm

This means that the reaction is 1st order respect to A and 0th order respect to B .

<u>PART B </u>

By the molecular kinetics theory, if an increment in the temperature occurs, the molecules will have greater kinetic energy and, consequently, will move faster. Thus, the possibility of colliding with another molecule increases. These collisions are necessary for the reaction. Therefore, an increase in temperature necessarily produces an increase in the reaction rate.

4 0
3 years ago
What is an equilibrium constant
skelet666 [1.2K]
The equilibrium constant<span> of a chemical reaction is the value of the reaction quotient when the reaction has reached </span>equilibrium<span>. An </span>equilibrium constant<span> value is independent of the analytical concentrations of the reactant and product species in a mixture, but depends on temperature and on ionic strength.</span>
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Chlorinated hydrocarbon pesticides, such as DDT, were introduced during World War II to control insects in agricultural crops. A
faltersainse [42]
Except:they are safe for all organisms except insect pest
7 0
4 years ago
BrainlieSTTTTTT A gas is originally stored at a pressure of 25 atm with a volume of 3 L. If the pressure were increased to 75 at
Crazy boy [7]

Explanation:

Apply Boyle's Law :-

P1V1 = P2V2

  • Where P1 is 25 atm
  • V1 is 3L
  • P2 is 75 atm
  • V2 is what we need to find out.

25 × 3 = 75 × V2

\tt{V_2 = \dfrac{ 25 \times 3}{75}}

\tt{V_2 = \dfrac{75}{75}}

<u>So, the answer is d) Part, 1L .</u>

Hope it helps :)

3 0
3 years ago
In nature, oxygen has three common isotopes. The atomic masses and relative abundances of these isotopes are given in the table
Vaselesa [24]

Answer: The average atomic mass of oxygen is 15.999 amu

Explanation:

Mass of isotope O-16 = 15.995 amu

% abundance of isotope O-16= 99.759 % = \frac{99.759}{100}=0.99759

Mass of isotope O-17 = 16.995 amu

% abundance of isotope O-17 = 0.037% = \frac{0.037}{100}=0.00037

Mass of isotope O-18 = 17.999 amu

% abundance of isotope O-18 = 0.204% = \frac{0.204}{100}=0.00204

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[(15.995\times 0.99759)+(16.995\times 0.00037)+(17.999 \times 0.00204)]

A=15.999

Thus the average atomic mass of oxygen is 15.999 amu

5 0
3 years ago
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