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marusya05 [52]
3 years ago
5

BrainlieSTTTTTT A gas is originally stored at a pressure of 25 atm with a volume of 3 L. If the pressure were increased to 75 at

m, what would be the new volume of the gas?
a.8.333 L
b.1 L
c.75 L
d.1 L
Chemistry
1 answer:
Crazy boy [7]3 years ago
3 0

Explanation:

Apply Boyle's Law :-

P1V1 = P2V2

  • Where P1 is 25 atm
  • V1 is 3L
  • P2 is 75 atm
  • V2 is what we need to find out.

25 × 3 = 75 × V2

\tt{V_2 = \dfrac{ 25 \times 3}{75}}

\tt{V_2 = \dfrac{75}{75}}

<u>So, the answer is d) Part, 1L .</u>

Hope it helps :)

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           \frac{HPO_{4}}{H_{2}PO_{4}} = 1.55 ............. (1)

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Now, putting the value of [HPO_{4}] from equation (1) into equation (2) as follows.

             1.55[H_{2}PO_{4}] + [tex][H_{2}PO_{4}] = 1 mM

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Putting the value of [H_{2}PO_{4}] in equation (1) we get the following.

                     0.392 mM + [HPO_{4}] = 1 mM

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