Question

BrainlieSTTTTTT A gas is originally stored at a pressure of 25 atm with a volume of 3 L. If the pressure were increased to 75 atm, what would be the new volume of the gas?
a.8.333 L
b.1 L
c.75 L
d.1 L

Answer 1

Explanation:

Apply Boyle's Law :-

P1V1 = P2V2

• Where P1 is 25 atm
• V1 is 3L
• P2 is 75 atm
• V2 is what we need to find out.

25 × 3 = 75 × V2

$\tt{V_2 = \dfrac{ 25 \times 3}{75}}$

$\tt{V_2 = \dfrac{75}{75}}$

So, the answer is d) Part, 1L .

Hope it helps :)