The path of the raction occurs on the basis of mass of the nuclei involved in reaction.
In case of nuclear fusion, two or more nuclei having less mass fuse(combine, join) together to form a new nuclei(heavier mass but it is relatively stable). During fusion, matter is not conserved because some of the matter is converted into energy(light). This reaction evolves a huge amount of energy and there comes Einstein's famous Energy-mass equivalence formula E=mc^2! :D. The nuclear reaction occuring in stars(including our sun ) is "fusion".
Fission occurs with heavier nuclei such as that of Uranium-235. Which splits into smaller subatomic particles like gamma, neutrons and enormous amount of energy.
Both, Fission and Fusion releases enormous amount of energy and modern nuclear weapons works on the principle of nuclear fission.
Answer:
The induced current in the loop is 1.2 A
Explanation:
Given;
length of the wire, L = 24 cm = 0.24 m
resistance of the wire, R = 0.14 Ω.
magnetic field strength, B = 0.55 T
time, t = 15 ms = 15 x 10⁻³ s
Circumference of a circle is given as;
L = 2πr
0.24 = 2πr
r = 0.24 / 2π
r = 0.0382 m
Area of a loop is given as;
A = πr²
A = π (0.0382)²
A = 0.004585 m²
Induced emf is given as;
Ф = ΔB x A
Ф = ( 0 - 0.55 T) x 0.004585 m²
Ф = -0.002522 T.m²
According to ohm's law;
V = IR
Where;
I is current
The induced current in the loop is calculated as;
I = V / R
I = 0.168 / 0.14
I = 1.2 A
Therefore, the induced current in the loop is 1.2 A
Answer:
28 grams
Explanation:
The equation for the reaction is
3H(2) + N(2) -> 2NH(3)
Then we have.
The molar mass, M of ammonia is 17 g/mol.
34 grams of ammonia, NH3 then would be
34 g / 17 g/mol
= 2 moles
2 moles of ammonia will be obtained from
(2 * 1) / 2
= 1 mole of nitrogen
The molar masses of nitrogen is 28 g/mol
2 moles of nitrogen corresponds to 1 * 28 = 28 grams.
Answer:
W = Q * V work done on charge Q
A. W = .5 C * 1.5 V = .75 Joules
B. P = W / t = .75 J / 1 sec = .75 Watts
