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Ronch [10]
3 years ago
11

What does the magnitude of centripetal acceleration depend on ?

Physics
1 answer:
MariettaO [177]3 years ago
3 0

Explanation:

Centripetal acceleration ac is the acceleration experienced while in uniform circular motion. It always points toward the center of rotation. It is perpendicular to the linear velocity v and has the magnitude ac=v2r;ac=rω2 a c = v 2 r ; a c = r ω 2 .

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What happens to a theory as new evidence is found?
algol13
New evidence may support the theory -> then nothing

New evidence conflicts with the theory => rework theory / create a new one
6 0
3 years ago
After release of jet, energy is lost by the engine. How principle of conservation of energy is obeyed in this condition.​
HACTEHA [7]

Answer:

The principle of conservation of energy states that in a closed system, the energy can neither be created nor destroyed between interacting particles and remains constant or transformed from one form to another

In the jet engine, the release of jet changes the number of interacting particles in the engine, and given that energy cannot be created in the instantaneously closed system of the engine, energy is carried away and therefore lost by particles in the jet exhaust

The conservation of energy principle is therefore obeyed in the condition in which the jet engine losses energy by the release of jet

Explanation:

5 0
2 years ago
two horses are pulling a 325 kg wagon, initially at rest. The horses exert 250 N and 178 N forward forces, respectively. Ignorin
Dovator [93]

Answer:

AFter 3.5 s, the wagon is moving at:   4.62\,\,\frac{m}{s}

Explanation:

Let's start by finding first the net force on the wagon, and from there the wagon's acceleration (using Newton's 2nd Law):

Net force = 250 N + 178 N = 428 N

Therefore, the acceleration from Newton's 2nd Law is:

F=m\,*\,a\\a = \frac{F}{m} \\a= \frac{428}{325}\, \frac{m}{s^2} \\a\approx 1.32 \,\,\frac{m}{s^2}

So now we apply this acceleration to the kinematic expression for velocity in an object moving under constant acceleration:

v_f=v_i+a\,*\,t\\v_f=0+1.32\,*\,3.5\,\,\frac{m}{s} \\v_f=4.62\,\,\frac{m}{s}

7 0
3 years ago
The wind is blowing horizontally at 30 m / s in a storm at P o , 20°C toward a wall, where it comes to a stop (stagnation) and l
aleksklad [387]

Answer:

 To=20.44 °C    

Explanation:

Given that

Velocity , v= 30 m/s

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We know that specific heat capacity for air ,Cp=1.005 kJ/kg.K

By using energy conservation ,the stagnation temperature is given as

T_0=T+\dfrac{v^2}{2C_p}

Now by putting the values in the above equation we get

T_0=(20+273)+\dfrac{30^2}{2\times 1.005\times 1000}\ K

To= 293.44 K

To= 293.44 - 273 °C

To=20.44 °C

Therefore the stagnation temperature will be 20.44 °C.

3 0
3 years ago
Which of the following describes wavelength?
blagie [28]
D. The number of wave that pass a point in a given amount of time
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3 years ago
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