The first one is B
and the second one is A hope this helps
I think the answer is option 2
Answer:
a) v = 75 ft / s
, b) v = 55 ft / s
, c) Δx = 1000 ft
Explanation:
We can solve this exercise with the expressions of kinematics
a) average speed is defined as the distance traveled in a given time interval
v = (x₂-x₁) / (t₂-t₁)
v = (550 - 400) / (10 -8)
v = 75 ft / s
b) we repeat the calculations for this interval
v = (550 - 0) / (10 -0)
v = 55 ft / s
c) we clear the distance from the average velocity equation
Δx = v (t₂ -t₁)
Δx = 100 (20-10)
Δx = 1000 ft
The Earth's radius is 6371 km. So that's our distance from the center when we're on the surface.
The Shuttle astronaut's distance from the center, when s/he's in orbit, is 330 km greater ... that's 6701 km.
The force of gravity is inversely proportional to the distance between the center of the Earth and the center of the astronaut. So, in orbit, it's
(6371/6701)^2 = 90.4 %
of its value on the surface.
Answer:
30 m
Explanation:
The speed is uniform, so there's no acceleration. Therefore:
Distance = rate × time
d = 1.5 m/s × 20 s
d = 30 m