Answer:
Explanation:
=10°C,
=93.33°C
Q=500 btu=527.58 KJ
If we assume that air is ideal gas PV=mRT, ΔU=
Actually this is closed system so work will be zero.
Now fro first law
Q=ΔU=+W
⇒Q=
527.58 =
m=4.9kg
PV=mRT
(
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Complete swap_bits function which swaps bits at odd and even positions of an integer (32 bits). In other words, every even posit
1 answer:
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Answer:
The plot of the function production rate m(t) (in kg/min) against time t (in min) is attached to this answer.
The production rate function M(t) is:
(1)
The Laplace transform of this function is:
(2)
Explanation:
The function of the production rate can be considered as constant functions by parts in the domain of time. To make it a continuous function, we can use the function Heaviside (as seen in equation (1)). To join all the constant functions, we consider at which time the step for each one of them appears and sum each function multiply by the function Heaviside.
For the Laplace transform we use the following rules:
(3)
(4)
Answer:
Explanation:
The mixing chamber can be modelled by applying the First Law of Thermodynamics:
Since that mass flow rate of water at inlet 1 is the only known variable, the expression has to be simplified like this:
Besides, the following expression derived from the Principle of Mass Conservation is presented below:
Then, the expression is simplified afterwards:
Specific enthalpies are obtained from steam tables and described as follows:
State 1 (Superheated vapor)
State 2 (Saturated liquid)
State 3 (Liquid-Vapor mixture)
The ratio of the stream at state 2 to the stream at state 1 is:
The mass flow rate of the saturated liquid is: