Answer:
15.64 MW
Explanation:
The computation of value of X that gives maximum profit is shown below:-
Profit = Revenue - Cost
= 15x - 0.2x 2 - 12 - 0.3x - 0.27x 2
= 14.7x - .47x^2 - 12
After solving the above equation we will get maximum differentiate for profit that is
14.7 - 0.94x = 0
So,
x = 15.64 MW
Therefore for computing the value of X that gives maximum profit we simply solve the above equation.
Answer: The exit temperature of the gas in deg C is
.
Explanation:
The given data is as follows.
= 1000 J/kg K, R = 500 J/kg K = 0.5 kJ/kg K (as 1 kJ = 1000 J)
= 100 kPa, 

We know that for an ideal gas the mass flow rate will be calculated as follows.

or, m = 
=
= 10 kg/s
Now, according to the steady flow energy equation:




= 5 K
= 5 K + 300 K
= 305 K
= (305 K - 273 K)
= 
Therefore, we can conclude that the exit temperature of the gas in deg C is
.
Answer: heat loss through wall is 16.58034kW
Temperature of inside wall surface is 47°c
Temperature of outside wall surface is -2.7°c
Explanation:detailed calculation and explanation is shown in the image below.
Answer:
reservoir is 727°C, then low temperature
Explanation:
Efficiency for any Heat engine = Work done by engine / Heat provided to the engine
Also, for a carnot engine derived formula for Carnot Engine
= 1- T2/T1
Where, T2 = sink reservoir temperature
and T1 = source reservoir temperature
727° C = 1000 K
So, 0.75 = 1-T2 / 1000
So, T2 = 1000*0.25 = 250 K = -23 Kelvin