Answer:
![27.164 lb/in^2](https://tex.z-dn.net/?f=27.164%20lb%2Fin%5E2)
Explanation:
We are given that
Gauge pressure at 3.4 degree Celsius,P=![24lb/in^2](https://tex.z-dn.net/?f=24lb%2Fin%5E2)
We have to find the gauge pressure in tire when the temperature rises to 26 degree Celsius.
Atmospheric pressure=![14.7lb/in^2](https://tex.z-dn.net/?f=14.7lb%2Fin%5E2)
![P_1=P+14.7=24+14.7=38.7lb/in^2](https://tex.z-dn.net/?f=P_1%3DP%2B14.7%3D24%2B14.7%3D38.7lb%2Fin%5E2)
K=273+Degree Celsius
![T_1=3.4+273=276.4 K](https://tex.z-dn.net/?f=T_1%3D3.4%2B273%3D276.4%20K)
![T_2=26+273=299K](https://tex.z-dn.net/?f=T_2%3D26%2B273%3D299K)
![P_2=\frac{P_1T_2}{T_1}](https://tex.z-dn.net/?f=P_2%3D%5Cfrac%7BP_1T_2%7D%7BT_1%7D)
![P_2=\frac{38.7\times 299}{276.4}](https://tex.z-dn.net/?f=P_2%3D%5Cfrac%7B38.7%5Ctimes%20299%7D%7B276.4%7D)
![P_2=41.864 lb/in^2](https://tex.z-dn.net/?f=P_2%3D41.864%20lb%2Fin%5E2)
Gauge pressure in tire when the temperature rises to 26 degree Celsius.=![41.864-14.7=27.164lb/in^2](https://tex.z-dn.net/?f=41.864-14.7%3D27.164lb%2Fin%5E2)
In the experiment of free fall bob released a bag of mass 1 lb
so here we can say that initial speed of the bag is Zero
time taken by the bag to free fall is given as
t = 1.5 s
also the acceleration of free fall is given as
a = 9.8 m/s^2
now we will use kinematics equation here for finding the distance of free fall
![d = v_i * t + \frac{1}{2} at^2](https://tex.z-dn.net/?f=d%20%3D%20v_i%20%2A%20t%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20at%5E2)
![d = 0 + \frac{1}{2}*9.8* 1.5^2](https://tex.z-dn.net/?f=d%20%3D%200%20%2B%20%5Cfrac%7B1%7D%7B2%7D%2A9.8%2A%201.5%5E2)
![d = 4.9 * 2.25](https://tex.z-dn.net/?f=d%20%3D%204.9%20%2A%202.25)
![d = 11.025 m](https://tex.z-dn.net/?f=d%20%3D%2011.025%20m)
so the bag will fall down by total distance of 11.025 m from its initial released position.