A passenger on a jet airplane claims to be able to walk at a speed in excess of 500 mph. Can this be true?

A hot-air balloon is rising upward with a constant speed of 2.85 m/s. When the balloon is 2.50 m above the ground, the balloonis

NISA [10]

Answer:

Explanation:

You have to declare which way is plus -- up or down. I will use down.

vi = - 2.85 The balloon is going up. That is the minus direction.

a = 9.81

d = 2.50 meters distance in this case is from the object to the ground.

d = vi*t + 1/2 a t^2

-2.50 = -2.85*t + 1/2 * 9.81 * t^2

-2.50 = -2.85*t + 4.905 * t^2 transfer the left to the right.

-4.905 t^2 + 2.85*t + 2.50 = 0

Use the quadratic formula to solve for t.

It turns out that t = 1.06

5 0

3 years ago

Co (5. 00 g) and co2 (5. 00 g) were placed in a 750. 0 ml container at 50. 0 °c. The partial pressure of co in the container was

konstantin123 [22]

Use PV = nRT and solve for P.
n = grams/molar mass = 5.00/molar mass CO2
Ignore the SO2.

But I think the answer it 6.74 atm

But I’m not saying but is but I’m just thinking this is the answer.

Goodluck!

6 0

2 years ago

A dog of mass 10 kg sits on a skateboard of mass 2 kg that is initially traveling south at 2 m/s. The dog jumps off with a veloc

Tasya [4]

Answer:

17 m/s south

Explanation:

$m_1$ = Mass of dog = 10 kg

$m_2$ = Mass of skateboard = 2 kg

v = Combined velocity = 2 m/s

$u_1$ = Velocity of dog = 1 m/s

$u_2$ = Velocity of skateboard

In this system the linear momentum is conserved

$(m_1+m_2)v+m_1u_1+m_2u_2=0\\\Rightarrow u_2=-\dfrac{(m_1+m_2)v+m_1u_1}{m_2}\\\Rightarrow u_2=-\dfrac{(10+2)2+10\times 1}{2}\\\Rightarrow u_2=-17\ m/s$

The velocity of the skateboard will be 17 m/s south as the north is taken as positive

3 0

3 years ago

What is the relationship between current and voltage in the filament of an incandescent light bulb?

lawyer [7]

An <span>incandescent light bulb is shown in the picture. The filament is the one labelled with number 3. This is a wire made usually of tungsten where the current passes to complete the flow of the electrons from the source to itself as the load. The tungsten material offers a quantity of resistance in ohms. The relationship between the current (I) , resistance (R) and voltage (V) is expressed by the Ohm's Law: V=IR. The voltage across the bulb is directly proportional to the current passing through it with the resistance of the material as its constant of proportionality.

In short, the voltage and current are related through the filament's resistance according to Ohm's Law.</span>

8 0

3 years ago

A plane monchromatic radio wave (lambda = 0.3 m) travels in vacuum along the positive x-axis, with an intensity I = 45 W/m2. Sup

Harrizon [31]

Answer:

$-5.78414\times 10^{-6}\ T$

Explanation:

$\epsilon_0$ = Permittivity of free space = $8.85\times 10^{-12}\ F/m$

c = Speed of light = $3\times 10^8\ m/s$

$\lambda$ = Wavelength = 0.3 m

T = Time period

f = Frequency

$E_0$ = Electric field

Intensity of electric field is given by

$I=\dfrac{1}{2}c\epsilon_0E_0^2\\\Rightarrow E_0=\sqrt{\dfrac{2I}{c\epsilon_0}}\\\Rightarrow E_0=\sqrt{\dfrac{2\times 45}{3\times 10^{8}\times 8.85\times 10^{-12}}}\\\Rightarrow E_0=184.11492\ N/C$

Magnetic field is given by

$B_0=\dfrac{E_0}{c}\\\Rightarrow B_0=\dfrac{184.11492}{3\times 10^8}\\\Rightarrow B_0=6.13716\times 10^{-7}\ T$

$k=\dfrac{2\pi}{\lambda}\\\Rightarrow k=\dfrac{2\pi}{0.3}\\\Rightarrow k=20.94\ /m$

$f=\dfrac{c}{\lambda}\\\Rightarrow f=\dfrac{3\times 10^{8}}{0.3}\\\Rightarrow f=1\times 10^{9}\ Hz$

$T=\dfrac{1}{f}\\\Rightarrow T=10^{-9}$

$\omega=\dfrac{2\pi}{T}\\\Rightarrow \omega=\dfrac{2\pi}{10^{-9}}\\\Rightarrow \omega=6283185307.17958\ rad/s$

Magnetic field in the z direction is given by (x=0)

$B_z=B_0(kx-\omega t)\\\Rightarrow B_z=6.13716\times 10^{-7}\times (0-6283185307.17958\times 1.5\times 10^{-9})\\\Rightarrow B_z=-5.78414\times 10^{-6}\ T$

The magnetic field at the origin is $-5.78414\times 10^{-6}\ T$

4 0

3 years ago