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Elena-2011 [213]
3 years ago
6

Find the equation of the line that is parallel to the line y (5,4) -2x +3 and passes through the point (5,4).

Mathematics
1 answer:
Natali5045456 [20]3 years ago
5 0

Answer:

y = -2x + 14

Step-by-step explanation:

Step 1:  Our line is parallel to this line, so it has the same slope, but a different  y-intercept, so set up the equation...

  y = -2x + b      

We are given a  point (x, y) of (5, 4), so plug that in and solve for b.  

 4 = -2(5) + b

    4 = -10 + b      (simplify)

        14 = b      (add 10 to both sides to isolate b)

    So the equation of our line is  y = -2x + 14

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3 years ago
What is the y-intercept, axis of symmetry and vertex of the following function.
Pepsi [2]

Complete the square:

F(x) = -3x² - 6x - 5

F(x) = -3 (x² + 2x) - 5

F(x) = -3 (x² + 2x + 1 - 1) - 5

F(x) = -3 ((x + 1)² - 1) - 5

F(x) = -3 (x + 1)² + 3 - 5

F(x) = -3 (x + 1)² - 2

The y-intercept has x-coordinate equal to 0, so it corresponds to the value of F(0) :

F(0) = -3 (0 + 1)² - 2 = -3 - 2 = -5

The axis of symmetry is the vertical line running through the vertex of this parabola, so we'll come back to this.

The vertex of the parabola is (-1, -2). This represents the maximum value of F(x), which follows from

(x + 1)² ≥ 0   ⇒   -3 (x + 1)² ≤ 0   ⇒   -3 (x + 1)² - 2 ≤ -2

This is to say, every point on the parabola has a y-coordinate no greater than -2.

As mentioned earlier, the axis of symmetry is the vertical line through the vertex, and its equation is determined by the x-coordinate of the vertex. Hence the AoS is the line x = -1.

4 0
2 years ago
Read 2 more answers
Find the exact value of the trigonometric function given that sinU=-7/25 and cosV=-4/5 (Both U and V are in Quadrant III)
Contact [7]

cosU:-

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\\ \rm\longmapsto \sqrt{1-cos^2V}=\sqrt{1-16/25}=3/4

As V lies in Q3

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So

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2 years ago
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julia-pushkina [17]
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This is the desired equation.  You could, if you wished, change this into slope-intercept form.
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Answer:

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Step-by-step explanation:

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