Answer : The percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.
Explanation :
First we have to calculate the number of atoms in 5.5 wt% Pb and 94.5 wt% of Sn.
As, 207.2 g of lead contains 
atoms
So, 5.5 g of lead contains 
atoms
and,
As, 118.71 g of lead contains atoms
So, 94.5 g of lead contains 
atoms
Now we have to calculate the percent composition of Pb and Sn in atom.
and,
Thus, the percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.
Answer:
V₂ = 1.86 L
Explanation:
Given data:
Initial volume = 4.30 L
Initial pressure = 1 atm
Initial temperature = 273.15 K
Final temperature = 302 K
Final volume = ?
Final pressure = 2.56 atm
Solution:
According to general gas equation:
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁T₂
/T₁ P₂
V₂ = 1 atm ×4.30 L × 302 K / 273.15 K × 2.56 atm
V₂ = 1298.6 atm.L.K / 699.26 K.atm
V₂ = 1.86 L
You need evidence to support a conclustion
Answer:
According to the law of conservation of mass, the mass of reactants will be equal to the mass of the products.
Explanation:
On a molecular level there is a lot of movement which in turn is the reason why heat is generated.
